What’s the answer to this

laila [671]

Answer:

8.2 units

Step-by-step explanation:

Given that the only information for our triangle are 2 sides and 1 angle, we must use the Law of Cosines to find side BC

Recall the Law of Cosines

$a^2=b^2+c^2-2bc\cdot cos(A)$

Identify angles and sides

$m\angle A=23^\circ\\a=BC=?\\b=AC=14\\c=AB=6$

Solve for side "a"

$a^2=b^2+c^2-2bc\cdot cos(A)\\\\a^2=14^2+6^2-2(14)(6)\cdot cos(23^\circ)\\\\a^2=196+36-168cos(23^\circ)\\\\a^2=222-168cos(23^\circ)\\\\a=\sqrt{222-168cos(23^\circ)}\\ \\a\approx8.2$

Therefore, the length of line segment BC is about 8.2 units

8 0

2 years ago

It costs $3.99 for 32 fl. oz. of soda. What is the unit rate? Your answer

Marrrta [24]

The unit rate means we need to find it per one soda can. So, 32/32 is one. We do the same to $3.99. $3.99/32 is about 13 cents.

Unit rate is: 13 cents per soda can

6 0

2 years ago

Jeanne babysits for $6 per hour. She also works as a reading tutor for $10 per hour. She is only allowed to work 20 hours per we

Ksenya-84 [330]

Part a) Use a system of inequalities to model the scenario

Let

x-------> represent babysitting hours

y-------> represent tutoring hours

we know that

$x+y \leq20$ --------> inequality $1$

$6x+10y \geq 75$ --------> inequality $2$

Part b) Use the model created in part A to create a graph representing Jeanne’s probable income earned and possible number of hours worked this week

we know that

$x+y \leq20$ --------> inequality $1$

This inequality represent Jeanne’s possible number of hours worked this week

Using a graph tool

the solution of this inequality is the shaded area

see the attached figure N $1$

$6x+10y \geq 75$ --------> inequality $2$

This inequality represent Jeanne’s probable income earned this week

Using a graph tool

the solution of this inequality is the shaded area

see the attached figure N $2$

Part c) Analyze the set of coordinate values that represent solutions for the model created in part A. Choose one of the coordinates within the solution and algebraically prove that the coordinate represents a true solution for the model

we have the system of inequalities

$x+y \leq20$ --------> inequality $1$

$6x+10y \geq 75$ --------> inequality $2$

the solution of the system of inequalities is the shaded area

using a graph tool

see the attached figure N $3$

Let

$A(10,10)$ ------> see the attached figure N $3$

The point belongs to the shaded area, so it is a system solution.

If the point is a solution, it must satisfy both inequalities.

Prove algebraically

$A(10,10)$

substitute the value of x and y in the inequalities

inequality $1$

$10+10 \leq20$

$20 \leq20$ ------> is ok

inequality $2$

$6*10+10*10 \geq 75$

$160 \geq 75$ -------> is ok

the point A satisfy both inequalities

therefore

the point A is a solution of the system

7 0

3 years ago

Write the slope-intercept form of the equation for the line.

OLEGan [10]

let's use those two endpoints in the line of (-5 , 2) and (5 , -1)

$\bf (\stackrel{x_1}{-5}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) \\\\\\ slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-2}{5-(-5)}\implies \cfrac{-3}{5+5}\implies -\cfrac{3}{10}$

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=-\cfrac{3}{10}[x-(-5)]\implies y-2=-\cfrac{3}{10}(x+5) \\\\\\ y-2=-\cfrac{3}{10}x-\cfrac{3}{2}\implies y=-\cfrac{3}{10}x-\cfrac{3}{2}+2\implies y=-\cfrac{3}{10}x+\cfrac{1}{2}$

7 0

3 years ago

Read 2 more answers

Avery's bottle holds 300 milliliters.

Kazeer [188]

Answer: you could make this really simple by dividing 300 by 4 to see how much 1/4 of that is and then subtracting 1/4 from 300 to see how much dashawn's water bottle holds.

300/4 =75 so 1/4 is equal to 75 mL

300-75=225mL

Dashawn's water bottle holds 225mL

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers