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3 years ago

Carlton ran 7 3/4 miles in 52 7/10 minutes. what is his average pace per minute?

Mathematics

1 answer:

SCORPION-xisa [38]3 years ago

5 0

Answer:

5/34 mi/min

Step-by-step explanation:

To find miles per minute, divide miles by minutes:

(7 3/4 mi)/(52 7/10 min) = (31/4 mi)/(527/10 min)

= (31/4)(10/527) mi/min = 310/2108 mi/min = 5/34 mi/min

Carlton's average pace was 5/34 miles per minute.

___

Since the given numbers are mixed numbers, we assume this is supposed to be a problem in fractions. Hence we have given the answer as a fraction. Its decimal value is about 0.14706. It is a repeating decimal with a 16-digit repeat.

You may have to do a little work to reduce the fraction 310/2108 to 5/34. You have to factor out a factor of 62. The numerator is 310=2·5·31, so that gives you a short list of factors to try with the denominator.

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Type the correct answer in the box. Use numerals instead of words. If necessary, use / for the fraction bar.

Sophie [7]

since the equation is c=9.5t, Sanjay paid c=9.5 x 14 shirts he bought. which =$133

6 0

3 years ago

Convert repeating decimal to fractions

timurjin [86]

Answer: 8/9

Step-by-step explanation: 0.888... can be simplified to 8/9.

6 0

3 years ago

Tom buys a shirt for $22.00 plus 7% sales tax. His cousin buys a shirt for $18.00 plus 4% sales tax. a. How much do Tom and his

likoan [24]

Tom is spending more on tax totaling 23.54
while his cousin is only spending 18.72

How to get tax with percent take base price ex:22+ 7%

transform percent into a decimal : .07

now multiply the decimal times base price : 22x0.07

tax is a $1.54 now add that to your base price 22

and you get your total $23.54

4 0

2 years ago

Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be

hodyreva [135]

Answer:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305$

And the sample deviation with the following formula:

$s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108$

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

$\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105$

And the sample deviation with the following formula:

$s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221$

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

$Abs = |340.221-115.108|= 225.113$

If we find the % of change respect the before case we have this:

$\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%$

So then is a big change.

8 0

3 years ago

Which is an example of a function?

Andreyy89

Step-by-step explanation:

the price of a piece of cloth and the length of the cloth

5 0

3 years ago