Answer:
It took 2 hours longer
Step-by-step explanation:
Answer:
a) 28
Step-by-step explanation:
Answer:
After reflection over the x-axis, we have the coordinates as follows;
A’ (5,-2)
B’ ( 1,-2)
C’ (3,-6)
Step-by-step explanation:
Here, we want to find the coordinates A’ B’ and C’ after a reflection over the x-axis
By reflecting over the x-axis, the y-coordinate is bound to change in sign
So if we have a Point (x,y) and we reflect over the x-axis, the image of the point after reflection would turn to (x,-y)
We simply go on to negate the value of the y-coordinate
Mathematically if we apply these to the given points, what we get are the following;
A’ (5,-2)
B’ ( 1,-2)
C’ (3,-6)
Convert to slope-intercept form.
5x - 2y = 10
2y = 5x - 10
y = (5/2)x - 5
So the slope is 5/2 and y-intercept is at (0, -5).
What is the math problem??