2 years ago

Is (4, -2) a solution to y = 4x - 15?

Mathematics

1 answer:

yKpoI14uk [10]2 years ago

3 0

Answer:

Step-by-step explanation:

hope this helps

i hope this is right

im 90% sure its right

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PLEASE HELP 15 POINTS...PLEASE HELP

sasho [114]

Answer:

-4

Step-by-step explanation: it is intercepting the -4 so i think -4 is the right answer

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3 years ago

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I don’t know if this is right, I’m stuck. Help!

STALIN [3.7K]

Answer:

Step-by-step explanation:

According to SohCahToa, cosine is adjacent over the hypotenuse.

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2 years ago

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tigry1 [53]

Answer: imma say 1

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2 years ago

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kolezko [41]

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2 years ago

Rewrite this standard form quadratic equation into vertex form by completing the square. Upload your work here to show your thin

Alex787 [66]

Solution :

Given the equation :

$y = x^2 - 6x+3$

$y=1(x^2 - 6x +n)+3$

$n = \left(\frac{b}{2}\right)^2$

$n = \left(\frac{6}{2}\right)^2$

n = 9

$y=1(x^2 - 6x +9-9)+3$

$y=1(x^2 - 6x +9)-9+3$

$y=1(x-3)^2- 6$

Therefore the vertex form of $y = x^2 - 6x+3$ is $y=1(x-3)^2- 6$ .

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2 years ago