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Kisachek [45]
3 years ago
6

Given that P = (5, 8) and Q = (6, 9), find the component form and magnitude of vector PQ.

Mathematics
1 answer:
max2010maxim [7]3 years ago
3 0

Answer:

<1 ,1>..., square root of two

Step-by-step explanation:

Component of vector PQ...,

; Q - P...where you subtract the x coordinate of Q by the x coordinate of P and the same for the y coordinate

; <(6-5),(9-8)>

; < 1,1 >

And the magnitude of PQ...,

;square root of( 1^2 + 1^2 )

;square root of 2

You might be interested in
15 - 1/2 x 2 equals 14, but i dont know the steps
zloy xaker [14]
Remember PEMDAS - parentheses, exponents, multiply, divide, add, subtract

because multiply come before subtract, your first step would be 1/2 x 2 = 1

next, you subtract -> 15 - 1 = 14

14 is your answer
3 0
3 years ago
A department store buys 200 shirts at a cost of $5,400 and sells them at a selling
jekas [21]

Number of shirts a department store bought = 200

Cost price of 200 shirts = $5400

Cost price of 1 shirt :

=\tt  \frac{5400}{200}

\color{plum} =\tt \$27

Thus, the cost price of one shirt = $27

Price at which the department store sold each shirt = $30

Which means :

▪︎Cost price of shirt = $27

▪︎Selling price of shrit = $30

Since selling price is greater than cost price, there was a markup in the price of the shirts.

We know that :

\color{hotpink}\tt \: markup \: percentage = \color{plum}  \frac{selling \: price - cost \: price}{cost \: price }  \times 100

Markup percentage in the price of the shirts :

=  \tt \frac{30 - 27}{27}  \times 100

=  \tt \frac{3}{27}  \times 100

= \tt  \frac{3 \times 100}{27}

= \tt  \frac{300}{27}

\color{plum} =  \tt11.1  \%

Thus, the percentage of markup = \tt 11.1  \%

Therefore, the percentage of markup in the shirt's price = \color{hotpink} \tt11.1  \%

3 0
3 years ago
Read 2 more answers
-x + 2y = 3<br> 2x – 3y = -6
s2008m [1.1K]

Answer:

x = -3

y = 0

Step-by-step explanation:

<u>Given</u><u> </u><u>equations</u><u> </u><u>:</u><u>-</u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u><u> </u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u>

<u>-x</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>-</u><u> </u><u>2</u><u>y</u><u> </u>

<u>x</u><u> </u><u>=</u><u> </u><u>2</u><u>y</u><u> </u><u>-</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u><u> </u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u>

<u>2</u><u>x</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>+</u><u> </u><u>3</u><u>y</u><u> </u>

<u>x =  \frac{ - 6 + 3y}{2}</u>

<u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>

<u>Equating</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>

<u>x</u><u> </u><u>=</u><u> </u><u>x</u><u> </u>

<u>2y - 3 =  \frac{ - 6 + 3y}{2}</u>

4y - 6 = -6 + 3y

4y - 3y = -6 + 6

y = 0

Putting value of y in ( iii )

x = 2y - 3

x = 2 ( 0 ) - 3

x = -3

4 0
3 years ago
Given:
bekas [8.4K]

Answer:

x = -4/9

Step-by-step explanation:

X + B = C

x + (-8/4) = (22/-9)

x = (8/4) - (22/9)

x = 2 - 22/9 = 18/9 - 22/9 = -4/9

3 0
3 years ago
Read 2 more answers
Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16). Wha
Rudik [331]
The point P has coordinates (x,y) = (-2,6) so x = -2 and y = 6

Replace x and y with those values into the rule given
So,
(x,y) ---> (x-2, y-16)
turns into
(-2,6) ---> (-2-2, 6-16) = (-4,-10)

P = (-2,6)
P ' = (-4,-10) 

The answer is -10 because your teacher just wants the y coordinate of point P'
4 0
3 years ago
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