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3 years ago

Given that P = (5, 8) and Q = (6, 9), find the component form and magnitude of vector PQ.

Mathematics

1 answer:

max2010maxim [7]3 years ago

3 0

Answer:

<1 ,1>..., square root of two

Step-by-step explanation:

Component of vector PQ...,

; Q - P...where you subtract the x coordinate of Q by the x coordinate of P and the same for the y coordinate

; <(6-5),(9-8)>

; < 1,1 >

And the magnitude of PQ...,

;square root of( 1^2 + 1^2 )

;square root of 2

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15 - 1/2 x 2 equals 14, but i dont know the steps

zloy xaker [14]

Remember PEMDAS - parentheses, exponents, multiply, divide, add, subtract

because multiply come before subtract, your first step would be 1/2 x 2 = 1

next, you subtract -> 15 - 1 = 14

14 is your answer

3 0

3 years ago

A department store buys 200 shirts at a cost of $5,400 and sells them at a selling

jekas [21]

Number of shirts a department store bought = 200

Cost price of 200 shirts = $5400

Cost price of 1 shirt :

$=\tt \frac{5400}{200}$

$\color{plum} =\tt \$27$

Thus, the cost price of one shirt = $27

Price at which the department store sold each shirt = $30

Which means :

▪︎Cost price of shirt = $27

▪︎Selling price of shrit = $30

Since selling price is greater than cost price, there was a markup in the price of the shirts.

We know that :

$\color{hotpink}\tt \: markup \: percentage = \color{plum} \frac{selling \: price - cost \: price}{cost \: price } \times 100$

Markup percentage in the price of the shirts :

$= \tt \frac{30 - 27}{27} \times 100$

$= \tt \frac{3}{27} \times 100$

$= \tt \frac{3 \times 100}{27}$

$= \tt \frac{300}{27}$

$\color{plum} = \tt11.1 \%$

Thus, the percentage of markup = $\tt 11.1 \%$

Therefore, the percentage of markup in the shirt's price = $\color{hotpink} \tt11.1 \%$

3 0

3 years ago

Read 2 more answers

-x + 2y = 3 2x – 3y = -6

s2008m [1.1K]

Answer:

x = -3

y = 0

Step-by-step explanation:

Given equations :- 

-x + 2y = 3 ....... ( i )

2x - 3y = -6 ....... ( ii )

From ( i ) 

-x + 2y = 3

-x = 3 - 2y

x = 2y - 3 ........ ( iii )

From ( ii ) 

2x - 3y = -6

2x = -6 + 3y

$x = \frac{ - 6 + 3y}{2}$

........ ( iv )

Equating ( iii ) and ( iv )

x = x

$2y - 3 = \frac{ - 6 + 3y}{2}$

4y - 6 = -6 + 3y

4y - 3y = -6 + 6

y = 0

Putting value of y in ( iii )

x = 2y - 3

x = 2 ( 0 ) - 3

x = -3

4 0

3 years ago

Given:

bekas [8.4K]

Answer:

x = -4/9

Step-by-step explanation:

X + B = C

x + (-8/4) = (22/-9)

x = (8/4) - (22/9)

x = 2 - 22/9 = 18/9 - 22/9 = -4/9

3 0

3 years ago

Read 2 more answers

Triangle PQR has vertices P(–2, 6), Q(–8, 4), and R(1, –2). It is translated according to the rule (x, y) → (x – 2, y – 16). Wha

Rudik [331]

The point P has coordinates (x,y) = (-2,6) so x = -2 and y = 6

Replace x and y with those values into the rule given
So,
(x,y) ---> (x-2, y-16)
turns into
(-2,6) ---> (-2-2, 6-16) = (-4,-10)

P = (-2,6)
P ' = (-4,-10)

The answer is -10 because your teacher just wants the y coordinate of point P'

4 0

3 years ago