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Mama L [17]
3 years ago
10

A father walks 36 miles in 12 hours while his son covers the same distance on a bicycle at twice the father's rate of speed. At

this rate, how many miles would the bicycle rider travel in 9 hours?
A.52 1/2 miles B. 29 1/2 miles C. 48 miles D.54 miles

Thx! Asvab Q. :)
Mathematics
2 answers:
anygoal [31]3 years ago
5 0

it would be d.)54 miles

denis-greek [22]3 years ago
3 0
6 miles per hour °9 hours = 54 miles
so the answer is
D. 54 miles
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Pls help I need to find the missing sides?!!
sladkih [1.3K]

Answer:

The missing sides are 13 (small) and 2424 (big)

Step-by-step explanation:

The bigger triangle is bigger by 2 so multiply or divide the sides you do know by 2 to find the missing sides.

BC=12

ED= 12*2= 24

FD= 26

AC= 26/2= 13

4 0
3 years ago
If a = 2.3 units, b = 4 units, c = 6 units, and d = 8 units, what is the volume of the two prisms?
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2 years ago
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Irina-Kira [14]

Answer:

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2 years ago
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Find the area of the regular polygon. Round to the nearest tenth.
mojhsa [17]

Given:

Side length = 12 in

To find:

The area of the regular polygon.

Solution:

Number of sides (n) = 6

Let us find the apothem using formula:

$a=\frac{s}{2 \tan \left(\frac{180^\circ}{n}\right)}

where s is side length and n is number of sides.

$a=\frac{12}{2 \tan \left(\frac{180^\circ}{6}\right)}

$a=\frac{6}{ \tan (30^\circ)}

$a=\frac{6}{ \frac{1}{\sqrt{3} }}

$a=6\sqrt{3}

Area of the regular polygon:

$A=\frac{1}{2}(\text { Perimeter })(\text { apothem })$

$A=\frac{1}{2}(6 \times 12)(6\sqrt{3} )

$A=\frac{1}{2}(72)(6\sqrt{3} )

A=216 \sqrt{3}

A=374.1 in²

The area of the regular polygon is 374.1 in².

4 0
3 years ago
Find the measure of the indicated angle to the nearest degree 9 25
SCORPION-xisa [38]

Answer:

1. 34.4°

2. 18.8°

3. 37.7°

4. 36.6°

5. 40.6°

6. 7.5

7. 12.3

8. 14.7

9. 22.0

10. 6.3

Step-by-step explanation:

1. The missing angle is found by the use of the sine.

Sine ∅= opposite/ hypotenuse

=13/23

sin⁻¹(13/23)=34.4°

2. The missing angle is calculated by the use of the tan.

Tan∅=opposite/adjacent

=17/50

Tan⁻¹(17/50)=18.8°

3. The missing angle is calculated by the use of the tan.

Tan∅=opposite/adjacent

=17/22

Tan⁻¹ (17/22) = 37.7°

4. The missing angle is calculated by the use of the tan.

Tan∅=opposite/adjacent

=21/28

Tan⁻¹ (21/28)=36.9°

5. The missing angle is calculated by the use of the tan.

Tan∅=opposite/adjacent

=24/28

Tan⁻¹ (24/28) = 40.6°

6. Missing side is calculated by considering the tan of 58°

Tan 58°=12/x

x=12/Tan 58°

=7.5

7.  Missing side is calculated by considering the sine of 43°

Sin 43°= opposite / hypotenuse

Sin 43 =x/18

x= 18 Sin 43

=12.3

8.  Missing side is calculated by considering the sine of 62°

Sin 62° = 13/x

x=13/Sin 62°

=14.7

9.  Missing side is calculated by considering the tan of 36°

Tan 36°= 16/x

x=16/Tan 36°

=22.0

10. Missing side is calculated by considering the sine of 23°

Sin 23° = x/16

x=16 Sin 23

=6.3

8 0
3 years ago
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