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prohojiy [21]
3 years ago
8

Help me.what is the answer?

Mathematics
2 answers:
kolbaska11 [484]3 years ago
3 0

Answer:

I believe its 1.5

Step-by-step explanation:

Hope it helps srry if im wrong.

Sonbull [250]3 years ago
3 0

Answer:

which principle prevents a brach from abusing  its power

Step-by-step explanation:

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FlybynightSavings.com is offering a savings account that pays 33% compounded continuously. How much interest would a deposit of
pychu [463]
The exact calculations:
Principal, P=3000
interest rate = 33% per year
Period, t=10 years

Future value
F=Pe^(it)
=3000e^(0.33*10)
=81337.92

Interest 
= future value - principal
= 81337.92-3000
= 78337.92  (to the nearest cent)


6 0
3 years ago
Forty more than the product of 2 and a number is twelve. What is the number?
posledela

Answer:

Logically, the answer is either 12 or 42

3 0
2 years ago
Given f(x) = 2x² + 4 and g(x) = 3x – 1 ……<br> What is (fg)(x)? <br><br> Show your work.
Lelu [443]

Answer:

(fg)(x) = 6x³ - 2x² + 12x - 4

Step-by-step explanation:

( f g ) ( x ) = f ( x ) * g ( x )

f(x) = 2x² + 4

g(x) = 3x – 1

( f g ) ( x ) = (2x² + 4) (3x – 1)

               = 6x³ - 2x² + 12x - 4

6 0
3 years ago
I need help with this!!!!!!!!!!!
GREYUIT [131]

Answer:

D

Step-by-step explanation:

C=2PI R

Radius is 24

pi is 3.14

Then you just solve it which turns out to be 150.8

7 0
2 years ago
Read 2 more answers
A competitive knitter is knitting a circular place mat. The radius of the mat is given by the formula
Ilia_Sergeevich [38]

Answer: A. A'(t)=\frac{4356\pi}{(t+11)^{3}}-\frac{527076\pi}{(t+11)^{5}}

              B. A'(5) = 1.76 cm/s

Step-by-step explanation: <u>Rate</u> <u>of</u> <u>change</u> measures the slope of a curve at a certain instant, therefore, rate is the derivative.

A. Area of a circle is given by

A=\pi.r^{2}

So to find the rate of the area:

\frac{dA}{dt}=\frac{dA}{dr}.\frac{dr}{dt}

\frac{dA}{dr} =2.\pi.r

Using r(t)=3-\frac{363}{(t+11)^{2}}

\frac{dr}{dt}=\frac{726}{(t+11)^{3}}

Then

\frac{dA}{dt}=2.\pi.r.[\frac{726}{(t+11)^{3}}]

\frac{dA}{dt}=2.\pi.[3-\frac{363}{(t+11)^{2}}].\frac{726}{(t+11)^{3}}

Multipying and simplifying:

\frac{dA}{dt}=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}

The rate at which the area is increasing is given by expression A'(t)=\frac{4356\pi}{(t+11)^{3}} -\frac{527076\pi}{(t+11)^{5}}.

B. At t = 5, rate is:

A'(5)=\frac{4356\pi}{(5+11)^{3}} -\frac{527076\pi}{(5+11)^{5}}

A'(5)=\frac{4356\pi}{4096} -\frac{527076\pi}{1048576}

A'(5)=\frac{2408693760\pi}{4294967296}

A'(5)=1.76268

At 5 seconds, the area is expanded at a rate of 1.76 cm/s.

5 0
2 years ago
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