<u>Solution and Explanation:</u>
a) 51% of users of mobile phones use their phone at least once per hour,
It is a binomial distribution with n = 150, p = 0.51
mean = np = 150 multiply with 0.51 = 76.5
SD= sqrt(np(1-p) )= 6.1225
Since np and n(1-p) > 5, we can assume the distribution is normal.
B) please see the attached file.
c) It is a binomial distribution with n = 150, p = 0.02
mean = np = 150*0.02 = 3
SD= sqrt(np(1-p) )= 1.71464
Since np < 5, we cannot assume the distribution is normal.