The formula is
A=p (1+r/k)^kt
A future value 3000
P present value 150
R interest rate 0.025
T time?
3000=150 (1+0.025/12)^12t
Solve for t
3000/150=(1+0.025/12)^12t
Take the log
Log (3000/150)=log (1+0.025/12)×12t
12t=Log (3000/150)÷log (1+0.025/12)
T=(log(3,000÷150)÷log(1+0.025÷12))÷12
T=119.95 years
Answer:
-450
Step-by-step explanation:
0-300=-300
-300-150=-450
112 is 80% of 140.
80% can be written as 0.80 or 0.8.
how i got 140 is by finding the x value of this equation: 0.8x=112
to find the x, i divided 0.8 from both sides,
0.8 divided by 0.8 cancel out.
112 divided by 0.8 is 140.
therefore, 112 is 80% of 140
