All categories

3 years ago

Evaluate 2^2⋅4^3=Your answer

Mathematics

1 answer:

ivanzaharov [21]3 years ago

6 0

Answer:

256

Step-by-step explanation:

First, handle the exponent:

2²=4 (2*2=4) and 4³=64 (4*4=16*4=64)

Now multiply those two outcomes:

4*64=256

This equation is also known as 4⁴

You might be interested in

I need help solving for the angle.

ohaa [14]

Use a protracter :) hope this helps!

6 0

3 years ago

Which expression is equivalent to 1/2 x + (-70) - 2 1/4 x - (-2) *

katovenus [111]

Answer:

-7/4x-68

Step-by-step explanation:

8 0

3 years ago

The diagram shows the width and area of a rectangle.

Mademuasel [1]

Answer:

The answer can be explained here: theraleighregister.com/the-diagram-shows-the-width-and-area-of-a-rectangl.html

Step-by-step explanation:

8 0

3 years ago

Boxes of raisins are labeled as containing 22 ounces. Following are the weights, in the ounces, of a sample of 12 boxes. It is r

ZanzabumX [31]

Answer:

A 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

Step-by-step explanation:

We are given the weights, in the ounces, of a sample of 12 boxes below;

Weights (X): 21.88, 21.76, 22.14, 21.63, 21.81, 22.12, 21.97, 21.57, 21.75, 21.96, 22.20, 21.80.

Firstly, the pivotal quantity for finding the confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean weight = $\frac{\sum X}{n}$ = 21.88 ounces

s = sample standard deviation = $\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }$ = 0.201 ounces

n = sample of boxes = 12

$\mu$ = population mean weight

Here for constructing a 90% confidence interval we have used a One-sample t-test statistics because we don't know about population standard deviation.

So, 90% confidence interval for the population mean, $\mu$ is ;

P(-1.796 < $t_1_1$ < 1.796) = 0.90 {As the critical value of t at 11 degrees of

freedom are -1.796 & 1.796 with P = 5%}

P(-1.796 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.796) = 0.90

P( $-1.796 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

P( $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ) = 0.90

90% confidence interval for $\mu$ = [ $\bar X-1.796 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+1.796 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $21.88-1.796 \times {\frac{0.201}{\sqrt{12} } }$ , $21.88+1.796 \times {\frac{0.201}{\sqrt{12} } }$ ]

= [21.78, 21.98]

Therefore, a 90% confidence interval for the mean weight is [21.78 ounces, 21.98 ounces].

8 0

3 years ago

What is the length of if ? 8 in. 8.75 in. 10.25 in. 14 in.

quester [9]

Answer:

Diagram attached

AJ = 8.75 in.

Step-by-step explanation:

Since triangles HBA & HKJ are similar,

BH/AH = KH/JH

3 in /5.25 in = 8 in /JH

JH = 14 in

JA = JH - AH = JH - 5.25 in = 8.75 in

HJ = 14 in.

AJ = 14 in - 5.25 in

AJ = 8.75 in.

7 0

3 years ago

Evaluate 2^2⋅4^3=Your answer​

Evaluate 2^2⋅4^3=Your answer