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zalisa [80]
3 years ago
7

A volleyball of radius 13 inches fits exactly in a cylinder with the same radius. A sphere with a radius of 13 inches is inside

of a cylinder with a radius of 13 inches. The cylinder has a height of 26 inches. Inside the container there is empty space not taken up by the volleyball. What is the volume of that empty space? Use 3.14 for π and round the answer to the nearest cubic inch.
Mathematics
2 answers:
ArbitrLikvidat [17]3 years ago
5 0

Answer:

26in cylinder

Step-by-step explanation

A volleyball of radius 13 inches fits exactly in a cylinder with the same radius. ~26in cylinder. Inside the container there is empty space not taken up by the volleyball.

sp2606 [1]3 years ago
5 0

Answer:

B. 4,599

Step-by-step explanation:

Volume of empty space = Volume of cylinder - volume of sphere

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Answer:

Step-by-step explanation:

Image result for Whats is the difference between Billion and Milliard? ​

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4 0
3 years ago
You roll a dice three times what is the probability that you roll an even number on the first roll, and odd on the second roll a
Dafna1 [17]
<h3>Answer:</h3>

D. 1/24

<h3>Step-by-step explanation:</h3>

Assuming the die is fair and the events are independent, the probability of the series of events is the product of the probabilities of the individual events.

p(even) = 3/6 = 1/2

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Then the joint probability is ...

.. (1/2)·(1/2)·(1/6) = 1/24

7 0
3 years ago
A plane averaged 500 mph on a trip going east, but only 200 mph on the return trip. The total flying time in both directions was
adoni [48]

Let's assume time taken by plane on one way distance as 't'

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so, time taken in other direction =10.5-t

now, we are given

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=500t

total distance of other way is

=200(10.5-t)

now, we can that distance is same from both sides

so, we get

500t=200(10.5-t)

now, we can solve for t

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7 0
3 years ago
If log2 5 = k, determine an expression for log32 5 in terms of k.
lukranit [14]

Answer:

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Step-by-step explanation:

Let's start by using change of base property:

log_b(x)=\frac{log_a(x)}{log_a(b)}

So, for log_2(5)

log_2(5)=k=\frac{log(5)}{log(2)}\hspace{10}(1)

Now, using change of base for log_3_2(5)

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Using reduction of power property:

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As you can see the only difference between (1) and (2) is the coefficient \frac{1}{5} :

So:

\frac{log(5)}{log(2)} =k\\

log_3_2(5)=\frac{1}{5} \frac{log(5)}{log(2)} =\frac{1}{5} k

6 0
3 years ago
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