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zalisa [80]
2 years ago
7

A volleyball of radius 13 inches fits exactly in a cylinder with the same radius. A sphere with a radius of 13 inches is inside

of a cylinder with a radius of 13 inches. The cylinder has a height of 26 inches. Inside the container there is empty space not taken up by the volleyball. What is the volume of that empty space? Use 3.14 for π and round the answer to the nearest cubic inch.
Mathematics
2 answers:
ArbitrLikvidat [17]2 years ago
5 0

Answer:

26in cylinder

Step-by-step explanation

A volleyball of radius 13 inches fits exactly in a cylinder with the same radius. ~26in cylinder. Inside the container there is empty space not taken up by the volleyball.

sp2606 [1]2 years ago
5 0

Answer:

B. 4,599

Step-by-step explanation:

Volume of empty space = Volume of cylinder - volume of sphere

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3 years ago
All formulas have how many variables?
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Step-by-step explanation:

All formulas have how many variables?

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3 0
2 years ago
Sarah has 284 coins in a piggy bank with a total value of $22.78. Sarah has 173 pennies, 5 more dimes than nickels, the rest are
pickupchik [31]
Let P = number of coins of pennies (1 penny = 1 cent)
Let N = number of coins of nickels (1 nickel = 5 cents)
Let D = number of coins of dimes (1 dime = 10 cents)
Let Q = number of coins of quarters (1 quarter = 25 cents)

a) P + N + D + Q = 284 coins, but P = 173 coins, then:
173 + N + D + Q =284 coins
(1)  N + D + Q = 111 coins

b) D = N + 5 OR D - N =5 coins
(2) D - N = 5 coins

c) Let's find the VALUE in CENTS of (1) that is N + D + Q = 111 coins
5N + 10D + 25 Q = 2,278 - 173 (1 PENNY)
(3) 5N + 10D + 25Q = 2105 cents
Now we have 3 equation with 3 variables:

(1)  N + D + Q = 111 coins
(2) D - N = 5 coins
(3) 5N + 10D + 25Q = 2105 cents
Solving it gives:
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22 coins D ( x 10 = 220 cents)
72 coins D ( x 25 = 1,800 cents)
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proof:
that makes a total of 85+2201800+172 =2,278 c or $22.78




7 0
3 years ago
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