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3 years ago

The difference between the boiling and melting points of fluorine is 32 degrees C.

1 answer:

6 0

Let the melting point be x degree C.
-188-x= 32
-x=32+188
-x=220
x= -220
Hence, the melting point of fluorine is -220 degree C.

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Step-by-step explanation:

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2 years ago

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3 years ago

Find the solution of the given initial value problem. ty' + 2y = sin t, y π 2 = 9, t > 0 y(t) =

Helen [10]

For the ODE

$ty'+2y=\sin t$

multiply both sides by t so that the left side can be condensed into the derivative of a product:

$t^2y'+2ty=t\sin t$

$\implies(t^2y)'=t\sin t$

Integrate both sides with respect to t :

$t^2y=\displaystyle\int t\sin t\,\mathrm dt=\sin t-t\cos t+C$

Divide both sides by $t^2$ to solve for y :

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac C{t^2}$

Now use the initial condition to solve for C :

$y\left(\dfrac\pi2\right)=9\implies9=\dfrac{\sin\frac\pi2}{\frac{\pi^2}4}-\dfrac{\cos\frac\pi2}{\frac\pi2}+\dfrac C{\frac{\pi^2}4}$

$\implies9=\dfrac4{\pi^2}(1+C)$

$\implies C=\dfrac{9\pi^2}4-1$

So the particular solution to the IVP is

$y(t)=\dfrac{\sin t}{t^2}-\dfrac{\cos t}t+\dfrac{\frac{9\pi^2}4-1}{t^2}$

$y(t)=\dfrac{4\sin t-4t\cos t+9\pi^2-4}{4t^2}$

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2 years ago

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anyanavicka [17]

You need to solve this "system of linear equations." In other words, find a point (x,y) that satisfies both 4x-3y=17 and 2x-5y=-11.

Try solution by elimination. Multiply the 2nd equation by -2 to obtain -4x+5y=22. Add this result to the 1st equation. I'd suggest you write this out to see what is happening.

4x-3y=17

-4x+10y=22
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7y=39. Solving for y, we get y=39/7 (a rather awkward fraction).

Now find x. To do this, substitute 39/7 for y in either of the given equations. Solve the resulting equation for x.

Write your solution in the form (x, y): ( ? , 39/7).

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3 years ago

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aivan3 [116]

Answer:

Step-by-step explanation:

-3=t/-15

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2 years ago

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