Find f(t + 2) when f(x) = 3x +9.

1 answer:

8 0

Basically just substitute t+2 for every x

f(t+2)=3(t+2)+9
f(t+2)=3t+6+9
f(t+2)=3t+15

Idk where the square roots are supposed to come from tho

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