Answer:
0.049168726 light-years
Step-by-step explanation:
The apparent brightness of a star is
where
<em>L = luminosity of the star (related to the Sun)
</em>
<em>d = distance in ly (light-years)
</em>
The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.
Hence the apparent brightness of Alpha Centauri A is
According to the inverse square law for light intensity
where
light intensity at distance
light intensity at distance
Let
be the distance we would have to place the 50-watt bulb, then replacing in the formula
Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.
There is no power of 4 that is to 0
Answer:
A = 2, B = 1, C = 5, D = 3, E = 4
Step-by-step explanation:
Variety of workings including
Opposite angles are equal
90 degrees on a right angle
180 degrees in a straight line
135 in percentage out of 100% is 1.35%
To Check This Answer
in 135(135.) move the decimal twice to the left and it becomes 1.35 you then multiply that by 100 and it will give you 135. Therefore 1.35 will become a percent which is 1.35%