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hammer [34]
3 years ago
14

Which ordered pairs are solutions to the inequality x+3y≥−8?

Mathematics
1 answer:
Dima020 [189]3 years ago
6 0
I think the answer would be b
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sertanlavr [38]
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7 0
3 years ago
Plsss help me, ASAP, Thank you
ankoles [38]

Answer:

\frac{1}{16}  \frac{10}{9}

Step-by-step explanation:

a reciprocal is a number that when multiplied by a given number gives 1 as  product.

16 * x = 1

x = 1/16

9/10 * x = 1

x = 10/9

8 0
3 years ago
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Mrs. Music bought a dress priced at $98.00. If the sales tax is 6%, what is the total amount she paid for the dress?
daser333 [38]

Answer: $103.88

Step-by-step explanation:

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7 0
3 years ago
F(x) = -x times 9 +1 for x=-3
sineoko [7]
Substitute the given value into the function and evaluate.
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6 0
2 years ago
A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=2−x2. What are the dimensions of su
Paul [167]

Answer:

Step-by-step explanation:

Given that a rectangle is inscribed with its base on the x-axis and its upper corners on the parabola

y=2-x^2

the parabola is open down with vertex at (0,2)

We can find that the rectangle also will be symmetrical about y axis.

Let the vertices on x axis by (p,0) and (-p,0)

Then other two vertices would be (p,2-p^2) (-p,2-p^2) because the vertices lie on the parabola and satisfy the parabola equation

Now width = 2-p^2

Area = l*w = 2(2p-p^3)

Use derivative test

I derivative = 2(2-3p^2)

II derivative = -12p

Equate I derivative to 0 and consider positive value only since we want maximum

p = \sqrt{\frac{2}{3} }

Thus width= \sqrt{\frac{2}{3} }

Length =2\sqrt{\frac{2}{3} }

Width = 2-2/3 = 4/3

3 0
3 years ago
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