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Ilya [14]
4 years ago
12

The angle between the incident ray and the surface of a plane mirror is 20'. What is the total angle rotated by the incident ray

?
I don't understand the question. Needing an explanation.
Physics
1 answer:
Dahasolnce [82]4 years ago
7 0

Angle made by the light ray with the surface of mirror is given as

\theta_i = 90 - 20 = 70degree

now as we know as per law of reflection that

angle of incidence = angle of reflection

So here we can say that

\theta_i = \theta_r

\theta_r = 70 degree

now the total angle that reflected ray will rotate with respect to incident ray is known as angle of deviation

\delta =180 - \theta_i - \theta_r

\delta = 180 - 70 - 70 = 40 degree

so here reflected light will deviate by total angle of 40 degree fron its incident ray.

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A 40-gram block of copper at 95*C is placed in 105 g of water at an unknown temperature. After equilibrium is reached, the final
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5 0
3 years ago
An egg is thrown nearly vertically upward from a point near the cornice of a tall building. It just misses the cornice on the wa
bezimeni [28]

Answer:

15.325 m/s

11.9702153415 m

0

9.81 m/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s² = a

s=ut+\frac{1}{2}at^2\\\Rightarrow u=\dfrac{s-\frac{1}{2}at^2}{t}\\\Rightarrow u=\dfrac{-46-\frac{1}{2}\times -9.81\times 5^2}{5}\\\Rightarrow u=15.325\ m/s

The initial velocity of the egg is 15.325 m/s

v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-15.325^2}{2\times -9.81}\\\Rightarrow s=11.9702153415\ m

The maximum height is 11.9702153415 m

At the highest point velocity is zero.

Magnitude of acceleration on a freely falling body is always g = 9.81 m/s²

7 0
3 years ago
A 81 cm long brass rod has a diameter of 3 mm. The temperature of one end is 50 degrees higher than the other end. How much heat
harina [27]

Answer:

5.14 J

Explanation:

l = 81 cm = 0.81 m

diameter = 3 mm

Radius, r = 1.5 mm = 1.5 x 10^-3 m

Change in temperature, T2 - T1 = 50 degree

t = 1.8 minutes = 1.8 x 60 = 108 s

k = 109 W/mk

Heat transfer = K A (T2 - T1) t / l

H = 109 x 3.14 x 1.5 x 10^-3 x 1.5 x 10^-3 x 50 x 108 / 0.81

H = 5.14 J

3 0
3 years ago
A 1500 W radiant heater is constructed to operate at 115 V. (a) What will be the current in the heater? (b) What is the resistan
OlgaM077 [116]

Answer:

a) I = 13.04 A

b)  R = 8.82 ohms

c) 1291.87 kilocalories are generated an hour.

Explanation:

let P be the power of the heater, V be the voltage of the heater, I be the current of the heater, R be the resistance.

a) we know that:

P = I×V

I = P/V

  = (1500)/(115)

  = 13.04 A

Therefore, the current of the heater is 13.04 A

b) we now have voltage and current, according to Ohm's law:

R = V/I

  = (115)/(13.04)

  = 8.82 ohms

Therefore, the resistance of the heating coil is 8.82 ohms.

c) the number of kilocalories generated in one hour by the heater is just the energy the heater produces in one hour which is given by:

E = P×t

  = (1500)(1×60×60)

  = 5400000 J

since 1 calorie = 4.81 J

1 kilocalorie = 0.001 calories

E = 5400000/4.18 ≈ 1291866.029 calories ≈1291.87 kilocalories

Therefore, 1291.87 kilocalories are produced/generated in one hour.

8 0
3 years ago
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