Answer:
Dx = -0.5
Dy = -0.25
Explanation:
Two vectors are given in rectangular components form as follows:
A = i + 6j
B = 3i - 7j
It is also given that:
A - B - 4D = 0
so, we solve this to find D vector:
(i + 6j) - (3i - 7j) - 4D = 0
- 2i - j = 4D
D = - (2/4)i - (1/4)j
D = - (1/2)i - (1/4)j
<u>D = - 0.5i - 0.25j</u>
Therefore,
<u>Dx = -0.5</u>
<u>Dy = -0.25</u>
Answer:
Explanation:
Check attachment for solution
Answer:
n = 4 x 10¹⁸ photons
Explanation:
First, we will calculate the energy of one photon in the radiation:
![E = \frac{hc}{\lambda}\\\\](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7Bhc%7D%7B%5Clambda%7D%5C%5C%5C%5C)
where,
E = Energy of one photon = ?
h = Plank's Constant = 6.625 x 10⁻³⁴ J.s
c = speed of light = 3 x 10⁸ m/s
λ = wavelength of radiation = 567 nm = 5.67 x 10⁻⁷ m
Therefore,
![E = \frac{(6.625\ x\ 10^{-34}\ J.s)(3\ x\ 10^8\ m/s)}{5.67\ x\ 10^{-7}\ m}](https://tex.z-dn.net/?f=E%20%3D%20%5Cfrac%7B%286.625%5C%20x%5C%2010%5E%7B-34%7D%5C%20J.s%29%283%5C%20x%5C%2010%5E8%5C%20m%2Fs%29%7D%7B5.67%5C%20x%5C%2010%5E%7B-7%7D%5C%20m%7D)
E = 3.505 x 10⁻¹⁹ J
Now, the number of photons to make up the total energy can be calculated as follows:
![Total\ Energy = nE\\1.4\ J = n(3.505\ x\ 10^{-19}\ J)\\n = \frac{1.4\ J}{3.505\ x\ 10^{-19}\ J}\\](https://tex.z-dn.net/?f=Total%5C%20Energy%20%3D%20nE%5C%5C1.4%5C%20J%20%3D%20n%283.505%5C%20x%5C%2010%5E%7B-19%7D%5C%20J%29%5C%5Cn%20%3D%20%5Cfrac%7B1.4%5C%20J%7D%7B3.505%5C%20x%5C%2010%5E%7B-19%7D%5C%20J%7D%5C%5C)
<u>n = 4 x 10¹⁸ photons</u>