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3 years ago

Is 5,690 divisible by 10

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

4 0

Answer yes 569

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Josie is training for a race. The ratio of

anzhelika [568]

The number of minutes that Josie will take is 80 minutes.

Explanation:

Explanation:

Ratio of the number of minutes to the number of miles = $\frac{24}{3}$

Number of miles = 10

Number of minutes = ?

Let x be the number of minutes

According to the question,

$\frac{24}{3} = \frac{x}{10} \\\\x = \frac{240}{3} \\\\x = 80$

Therefore, the number of minutes that Josie will take is 80 minutes.

6 0

3 years ago

HELP WITH BOTH PARTSSSSSSSSS

const2013 [10]

Answer:

Wait... that's my name... whatever, here is the answer XD

Step-by-step explanation:

c+9.75=20.75 is the answer :D

Cost of his ticket is $20.75

4 0

3 years ago

Read 2 more answers

What is the area of the figure?

mrs_skeptik [129]

We see that the shape is made up of 2 shapes:
trapezoid and triangle
(trapezoid is on top of upside down triangle)

area of trapezoid=(1/2)(b1+b2)(h)
area of traignel=(1/2)(b)(h)

area of trapezoid
b1=14
b2=18
h= ok so total height=17 and 12 is taken up by triangle os therefor h=17-12=5

A=(1/2)(14+18)(5)
A=(1/2)(32)(5)
A=(16)(5)
A=(80)

now area of triangle
H=12
B=18
A=(1/2)(18)(12)
A=(9)(12)
A=108

add
80+108=188

total area=188mm^2

5 0

3 years ago

The sum of two integers is 74. The larger is 26 more than twice the smaller.Find the two integers

irina [24]

Let... the smaller integer be x

Then, the larger integer is 2x+26(Two times.. =2x, 26 more... is =2x+26

Both added is 74

2x+26=74

2x=74−26

2x=48

x=24

5 0

3 years ago

Read 2 more answers

What is the area of a triangle with vertices at (0, – 2), (8, – 2), and (9, 1)?

Luda [366]

ANSWER:

The area of the triangle with vertices at (0, – 2), (8, – 2), and (9, 1) is 12 square units.

SOLUTION:

Given, vertices of the triangle are A(0, -2), B(8, -2) and C(9, 1).

We have to find the area of the given triangle.

We know that,

$\text { Area of triangle }=\frac{1}{2}\left(x_{1}\left(y_{2}-y_{3}\right)+x_{2}\left(y_{3}-y_{1}\right)+x_{3}\left(y_{1}-y_{2}\right)\right)$

$\text { Where, }\left(x_{1}, y_{1}\right),\left(x_{2}, y_{2}\right),\left(x_{3}, y_{3}\right) \text { are vertices of the triangle. }$

Here in our problem, $\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right)=(0,-2),\left(\mathrm{x}_{2}, \mathrm{y}_{2}\right)=(8,-2) \text { and }\left(\mathrm{x}_{3}, \mathrm{y}_{3}\right)=(9,1)$

Now, substitute the above values in the formula.

$\text { Area of triangle }=\frac{1}{2}\left(x_{1}\left(y_{2}-y_{3}\right)+x_{2}\left(y_{3}-y_{1}\right)+x_{3}\left(y_{1}-y_{2}\right)\right)$

$=\frac{1}{2}(0(-2-1)+8(1-(-2))+9(-2-(-2))$

$=\frac{1}{2}(0+8(1+2)+9(2-2))$

$\frac{1}{2}(0 + 0 +24) = \frac{24}{12} = 2$

Hence, the area of the triangle is 12 sq units.

7 0

3 years ago