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Romashka [77]
3 years ago
5

WILL MARK BRAINLIEST

Mathematics
1 answer:
il63 [147K]3 years ago
8 0

Answer:

1) c 2)c 3)b

Step-by-step explanation:

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Write each fraction as a decimal. round to the nearest hundredth if necessary.
SashulF [63]

Answer:

0.375

1.4

3

1.66666666667

Step-by-step explanation:

Divide the numerator (top number) by the denominator (bottom).

3 0
4 years ago
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What is the value of x?<br><br><br><br> Enter your answer in the box.<br><br> x =
polet [3.4K]
The two angles are the same value. To find, think of the equation 3<em>x</em>+50=6<em>x</em>-10. Put the 6<em>x</em> to the other side of the equation. You shall get -3x+50=-10. Move the 50 to the other side, and you'll end up with -3<em>x</em>=-60. Divide each number by -3 to find <em>x</em> now. Your final answer will be <em>x=20</em>.

Answer: <em>x=20</em>
8 0
3 years ago
What is the volume of the right prism with height h=14 cm, if the base of the prism is a triangle ∆ABC with side AB = 9 cm and a
LenaWriter [7]

Answer:

378

Step-by-step explanation:

9*6=54 then 54/2=27. fnally 27*14=378

6 0
4 years ago
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Use the diagram and given information to answer the questions and prove the statement.
Greeley [361]

Answer:

See explanation

Step-by-step explanation:

<u> ASA Postulate (Angle-Side-Angle):</u>

If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.

Consider triangles XYB and ZYA. In these triangles

  • ∠X≅∠Z (given)
  • XY≅ZY (given)
  • ∠Y is common angle

By ASA Postulate, triangles XYB and ZYA are congruent. Congruent triangles have congruent corresponding sides, so

BX≅AZ

6 0
3 years ago
With full explanation from the internet like before<br> 3x2-6x+5=0
Elodia [21]

Answer:

\sf x=1+i\sqrt{\dfrac{2}{3}}   \ \quad and  \quad \:x=1-i\sqrt{\dfrac{2}{3}}

Explanation:

<u>Given Expression</u>:

  • 3x² - 6x + 5 = 0

Use the Quadratic Formula:

\sf x = \dfrac{ -b \pm \sqrt{b^2 - 4ac}}{2a}  \  \ when   \ \  ax^2 + bx + c = 0

<u>insert coefficients</u>

\Longrightarrow \sf x = \dfrac{-\left(-6\right)\pm \sqrt{\left(-6\right)^2-4\cdot \:3\cdot \:5}}{2\cdot \:3}

\Longrightarrow \sf x = \dfrac{\left6\right\pm \sqrt{-24} }{6}

\Longrightarrow \sf x = \dfrac{\left6\right\pm 2\sqrt{6}i}{6}

\Longrightarrow \sf x =1 \pm   i\dfrac{\sqrt{6} }{3}

\Longrightarrow \sf x=1+i\sqrt{\dfrac{2}{3}},  \quad 1-i\sqrt{\dfrac{2}{3}}

6 0
2 years ago
Read 2 more answers
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