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GREYUIT [131]
3 years ago
13

Pls help me solve this 8(x-1) = -2(x + 8)

Mathematics
2 answers:
bixtya [17]3 years ago
8 0

Answer:

x= -4/5

Step-by-step explanation:

first distribute on both sides

8x -8 = -2x -16

isolate x on one side

10x = -8

x = -8/10

you can simplify that fraction to get

x= -4/5

Dennis_Churaev [7]3 years ago
3 0
8 ( x - 1) = -2 ( x + 8)
8x - 8 = -2 ( x + 8)
Distribute ^
Distribute again
8x - 8 = -2 (x + 8)
8x - 8 = -2x -16
Add 8 to both sides of the equation
X = -4/5
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3 years ago
If a ball is thrown into the air with a velocity of 34 ft/s, its height (in feet) after t seconds is given by y = 34t − 16t2. Fi
Finger [1]

<u>ANSWER: </u>

If a ball is thrown into the air with a velocity of 34 feet per second, then velocity of the ball after 1 second is 2 feet per second

<u>SOLUTION: </u>

Given, a ball is thrown into the air with a velocity of 34 feet per second

Initial velocity (u) = 34 feet per second

And also given a relation between displacement and time = \mathrm{y}=34 \mathrm{t}-16 \mathrm{t}^{2} --- eqn 1

We need to find the velocity when t = 1 ; v = ?

We know that, v = u + at and \mathrm{s}=\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}

where v is instantaneous velocity and u is initial velocity

a is acceleration

t is time interval  

s is displacement

using the displacement and time relation eqn (1) we get

Now, when t = 1, displacement s = 34(1) – 16(1)

\mathrm{ut}+\frac{1}{2} \mathrm{at}^{2}=34-16

34 \times 1+\frac{1}{2} \times a \times 1^{2}=18

34+\frac{a}{2}=18

\begin{array}{l}{\frac{a}{2}=18-34} \\\\ {\frac{a}{2}=-16} \\ {a=-16 \times 2} \\ {a=-32}\end{array}

here, -ve sign indicates that object is in deceleration . so acceleration is -32 ft/s

now put a value in v = u + at

v = 34 + (-32)(1)

v = 34 – 32

v = 2 ft/s

Hence, velocity of the ball after 1 second is 2 ft/s

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