Question

A line passes through the points (1, 4) and (0, 2). What is its equation in slope-intercept form?

Answer 1

Slope-intercept form:  y = mx + b

(m is the slope, b is the y-intercept or the y value when x = 0 --> (0, y) or the point where the line crosses through the y-axis)

To find the slope (m), use the slope formula:

$m=\frac{y_2-y_1}{x_2-x_1}$     and plug in the two points

(0, 2) = (x₁, y₁)

(1, 4) = (x₂, y₂)

[lines usually go from left to right, so the point furthest to the left is the 1st point]

$m = \frac{y_2-y_1}{x_2-x_1}$

$m=\frac{4-2}{1-0}$

$m=\frac{2}{1}$

m = 2          Now that you know the slope, substitute/plug it into the equation

y = mx + b              Plug in 2 for "m"

y = 2x + b     To find b, plug in either of the two points into the equation, it doesn't matter which. I will use (0, 2)

2 = 2(0) + b

2 = b

y = 2x + 2

Answer 2

Answer:

y=1/2x+2

Step-by-step explanation:

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