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3 years ago

Can someone explain how to do this please? 3 I2x-3I+2=3

Mathematics

2 answers:

GarryVolchara [31]3 years ago

7 0

Answer:

x = 5/3 x = 4/3

Step-by-step explanation:

3 I2x-3I+2=3

Subtract 2 from each side

3 I2x-3I+2-2=3-2

3 I2x-3I=1

Divide by 3

3/3I2x-3I=1/3

I2x-3I=1/3

Now we have two solutions to an absolute value, a positive and a negative

2x-3 = 1/3 2x-3 = -1/3

Add 3 to each side

2x-3+3 = 1/3+3 2x-3+3 = -1/3+3

2x= 1/3+9/3 2x = -1/3 +9/3

2x = 10/3 2x = 8/3

Divide by 2

2x/2 = 10/3 *1/2 2x/2 = 8/3 *1/2

x = 5/3 x = 4/3

Dmitry [639]3 years ago

5 0

I think this is correct-scroll down through the picture

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SashulF [63]

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8 0

3 years ago

PLZ HELP ME BY THE END OF THE DAY

nlexa [21]

$3x^{2} +1=28$

Step 1 : subtract 1 from both sides

$3x^{2} =27$

Step 2 : Divide both sides by 3

$\frac{\frac{3x^{2} }{3} }{\frac{27}{3} }$

$x^{2} = 9$

Step 3 : Find the square root of 9

$\sqrt{9} = 3$

x= (-3,3)

remember negative × negative = positive

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3 years ago

Given the equation 6/x=3/k+2, and the constraints x ≠ 0 and k ≠-2, what is x in terms of k?

Veronika [31]

Answer:

A) 2k+4

Step-by-step explanation:

To solve for terms of x, we need to. she sure that x is on its own side while every other term is on the other side.

To start, we will cross multiply. If we have a/b=c/d, then ad=bc

We can perform the same calculation here,

6/x=3/(k+2)

6(k+2)=3x

Divide both sides by 3

2(k+2)=x

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3 years ago

A little help? What does Y equal? ( Giving Branliest )

elena-14-01-66 [18.8K]

Answer:

-4/3 = y

Step-by-step explanation:

-1/2 = 3/8y

Multiply each side by 8/3 to isolate y

-1/2 * 8/3 = 3/8y * 8/3y

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3 years ago

Read 2 more answers

Calculus piecewise function.

Kipish [7]

Part A

The notation $\lim_{x \to 2^{+}}f(x)$ means that we're approaching x = 2 from the right hand side (aka positive side). This is known as a right hand limit.

So we could start at say x = 2.5 and get closer to 2 by getting to x = 2.4 then to x = 2.3 then 2.2, 2.1, 2.01, 2.001, etc

We don't actually arrive at x = 2 itself. We simply move closer and closer.

Since we're on the positive or right hand side of 2, this means we go with the rule involving x > 2

Therefore f(x) = (x/2) + 1

Plug in x = 2 to find that...

f(x) = (x/2) + 1

f(2) = (2/2) + 1

f(2) = 2

This shows $\lim_{x \to 2^{+}}f(x) = 2$

Then for the left hand limit $\lim_{x \to 2^{-}}f(x)$ , we'll involve x < 2 and we go for the first piece. So,

f(x) = 3-x

f(2) = 3-2

f(2) = 1

Therefore, $\lim_{x \to 2^{-}}f(x) = 1$

===============================================================

Part B

Because $\lim_{x \to 2^{+}}f(x) \ne \lim_{x \to 2^{-}}f(x)$ this means that the limit $\lim_{x \to 2}f(x)$ does not exist.

If you are a visual learner, check out the graph below of the piecewise function. Notice the gap or disconnect at x = 2. This can be thought of as two roads that are disconnected. There's no way for a car to go from one road to the other. Because of this disconnect, the limit doesn't exist at x = 2.

===============================================================

Part C

You'll follow the same type of steps shown in part A.

However, keep in mind that x = 4 is above x = 2, so we'll deal with x > 2 only.

So you'd only involve the second piece f(x) = (x/2) + 1

You should find that f(4) = 3, and that both left and right hand limits equal this value. The left and right hand limits approach the same y value. The limit does exist here. There are no gaps to worry about when x = 4.

===============================================================

Part D

As mentioned earlier, since $\lim_{x \to 4^{+}}f(x) = \lim_{x \to 4^{-}}f(x) = 3$ , this means the limit $\lim_{x \to 4}f(x)$ does exist and it's equal to 3.

As x gets closer and closer to 4, the y values are approaching 3. This applies to both directions.

4 0

1 year ago