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marin [14]
3 years ago
14

Which of the following would eliminate the variable on the left side of the given equation?

Mathematics
2 answers:
uranmaximum [27]3 years ago
8 0
You'd have to add 19w in order to cancel out the -19w
aev [14]3 years ago
3 0
To eliminate the variable on the left you must make it equal zero because the variable is negative (-19w) you will need to add to get the variable to zero

So you will have to add positive 19 to cancel out the negative

So your answer is C add 19w
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Can someone help please? I really don't understand this.
zhannawk [14.2K]

Answer:

i don't know

Step-by-step explanation:

7 0
3 years ago
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At a local swimming pool, the diving board is elevated h = 9.5 m above the pool's surface and overhangs the pool edge by L = 2 m
beks73 [17]
<h2>Answer:</h2>

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}\\9.5=4.9t^{2}

and,

v_{x}=1.39a_{x}+2.5

<h2>Step-by-step explanation:</h2>

In the question,

Taking the elevation of pool along the y-axis, and length of the board along the x-axis.

On drawing the illustration in the co-ordinate system we get,

lₓ = 2 m

uₓ = 2.5 m/s

and,

h_{y}=9.5\,m

So,

From the equations of the laws of motion we can state that,

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}

So,

On putting the values we can say that,

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}\\9.5=(0)t+\frac{1}{2}(9.8)t^{2}\\t^{2}=\frac{9.5}{4.9}\\t^{2}=1.93\\t=1.39\,s

Now,

The <u>equation of the motion in the horizontal</u> can be given by,

v_{x}=u_{x}+a_{x}t\\v_{x}=2.5+a_{x}(1.39)\\So,\\v_{x}=1.39a_{x}+2.5

<em><u>Therefore, the equations of the motions in the horizontal and verticals are,</u></em>

s_{y}=u_{y}t+\frac{1}{2}a_{y}t^{2}\\9.5=4.9t^{2}

and,

v_{x}=1.39a_{x}+2.5

6 0
3 years ago
9·8·7! is equivalent to:<br><br> 9 x 8 x 7<br> 72 x 5,040<br> 504!
liq [111]

Answer:

\large\boxed{9\cdot8\cdot7!=72\times5,040}

Step-by-step explanation:

n!=1\cdot2\cdot3\cdot...\cdot n\\\\\text{Therefore}\\\\7!=1\cdot2\cdot3\cdot4\cdot5\cdot6\cdot7=5,040\\\\9\cdot8=72\\\\\text{Finally:}\\\\9\cdot8\cdot7!=72\times5,040

8 0
3 years ago
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Guys please this is my second time posting this I really need help. And if you answer this you can answer my other same question
spayn [35]

Answer: F and H I think are vertical

Step-by-step explanation:

I'm sorry i couldn't help you

4 0
3 years ago
The blades of a windmill turn on an axis that is 40 feet from the ground. The blades are 15 feet long and complete 3 rotations e
astraxan [27]

Answer:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

a = 15\ ft\\\\k = 40\ ft

y = 15sin(\frac{\pi}{10}t) + 40

Step-by-step explanation:

In this problem the amplitude of the sinusoidal function is given by the length of the blades.

a = 15\ ft

The mill is 40 feet above the ground, therefore the function must be displaced 40 units up on the y axis. So:

k = 40\ ft

We know that the blades have an angular velocity w = 3 rotations per minute.

One rotation = 2\pi

1 minute = 60 sec.

So:

w = \frac{3(2\pi)}{60}\ rad/s

w = \frac{\pi}{10}\ rad/s

Finally:

a is the _amplitude_(Length of the blades)_

The vertical shift, k, is the _Mill shaft height_

a = 15\ ft\\\\k = 40\ ft

y = 15sin(\frac{\pi}{10}t) + 40

3 0
3 years ago
Read 2 more answers
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