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jek_recluse [69]
3 years ago
11

A right triangle has a hypotenuse that measures 5 inches and one leg that measures 2 inches. What is the length of the missing l

eg?
Mathematics
1 answer:
jolli1 [7]3 years ago
8 0
Pythagorean theorem

c2 = a2 + b2
5^2 = 2^2 + b2
25 = 4 +b2
21 = b2
b = 4.6
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Solve this system of equations by graphing. First graph the equations, and then type the solution. y= x+3 y=2x
Yuliya22 [10]

Answer:

(3,6)

Step-by-step explanation:

Y=X+3

Y=X2

X+3=2X

X-2X= -3

-x=-3

x=3

then Y=2X

Y=2×3

Y=6

(3,6)

3 0
2 years ago
Select the correct answer.
vitfil [10]
Is there an image i don’t understand what expressions you’re asking for?
6 0
2 years ago
On his first three tests, Hiram got scores of 89, 95, and 90. His final test score brought his median score to 91.5. What was I
Elena-2011 [213]
The median is the middle score, it is also the average of the two middle scores when total number is even.

original 3 scores:  89, 90, 95  ----> median = 90

with final score:  89,90,X,95  ----> median = 91.5

(90+x)/2 = 91.5
90+x = 183
x = 93

Final score was a 93.
6 0
3 years ago
Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie
melamori03 [73]

Answer:

The complete solution is

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

y = e^{mx}

Differentiating with respect to x

y'= me^{mx}

Again differentiating with respect to x

y''= m ^2 e^{mx}

Putting the value of y, y' and y'' in left side of the differential equation

3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0

\Rightarrow 3m^2-8m-3=0

The auxiliary equation is

3m^2-8m-3=0

\Rightarrow 3m^2 -9m+m-3m=0

\Rightarrow 3m(m-3)+1(m-3)=0

\Rightarrow (3m+1)(m-3)=0

\Rightarrow m = 3, -\frac13

The complementary function is

y= Ae^{3x}+Be^{-\frac13 x}

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)    

For particular integral

y_p=\frac 1{(3D+1)(D-3)} .4

    =4.\frac 1{(3D+1)(D-3)} .e^{0.x}    [since e^{0.x}=1]

   =4\frac{1}{(3.0+1)(0-3)}      [ replace D by 0 , since L(0)≠0]

   =-\frac43

The complete solution is

y= C.F+P.I

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

4 0
2 years ago
Analyze the diagram below and complete the instructions that follow. (7x - 3) (12x -7) Solve for x.
yarga [219]

Answer:

Step-by-step explanation:

(7x-3)(12x-7)

we are solving for x and we are multiplying.

we start with the x's 7x*12x=  84x

-3*-7=21

so now we have

84x+21=0

the 0 is a placer for answering the question

we minus 21 to both sides

84x=-21

now we divide

84/-21= -4

x=-4

6 0
2 years ago
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