Answer:
Dimension of pools are length = 42 ft , width = 12 ft and depth = 8 ft that is 42ft × 12ft × 8 ft
Step-by-step explanation:
given that depth of pool = 8 ft
let say one side of pool that is width = x
so other side of pool that is lenght = 3.5x [ given ]
volume of rectangular swimming pool is same as amount of water required to fill the swimming pool = 4032 cubit ft
Volume of rectangular pool = length × width × depth of swimming pool
⇒ 4032 cubic ft = 3.5x × x × 8
⇒ 4032/(3.5 ×8 ) = x²
⇒x² = 144
⇒x = √144 = 12
⇒3.5x = 12 × 3.5 = 42
hence dimension of pools are length = 42 ft , width = 12 ft and depth = 8 ft that is 42ft × 12ft × 8 ft
Answer:
52
Step-by-step explanation:
find the area of each individual piece
top and bottom dimensions are 4 X 3- so each one is 12 inches squared
the left and right side dimensions are 4 X 2- each one is 8
the front and back dimensions are 3 X 2 each one is 6
Surface area- add all together
12+12+8+8+6+6= 52 in squared
<u>Angie buys</u>
1 Software package + 3 months of game play.
Each software package costs = $20.
Let us assume cost of one month of game play = $x.
Therefore, total cost to Angie for 1 Software package + 3 months of game play = 20*1 + 3x = 20 +3x.
<u> Kenny buys </u>
1 software package + 2 months of game play.
Therefore, total cost to Kenny for 1 software package + 2 months of game play = 20*1 + 2*x = 20+2x.
Their total cost = $115.
Adding their costs and set it equal to 115, we get
<h3>20 +3x + 20+2x = 115.</h3>
Now, we need to solve it for x.
40 + 5x = 115.
5x = 115 - 40.
5x = 75.
Dividing both sides by 5, we get
x= 15.
<h3>Therefore, $15 is the total cost of one month of game play.</h3>
About 10 pages
If you divide 292 / 28 since there is 28 days in 4 weeks
Answer:
$8
Step-by-step explanation:
Five student tickets cost $40
Price for each student tickets
= Total cost of five student tickets/5 students
=$40/5
=$8
Each student ticket cost $8