Explanation:
Given that,
Radius of circular path, r = 5 m
Centripetal acceleration, 
(a) Let v is the astronaut’s speed. The formula for the centripetal acceleration is given by :



v = 18.5 m/s
(b) Let T denotes the time period. It is given by :


T = 1.69 s
Let N is the number of revolutions. So,

So, the number of revolutions per minute is 35.5
(c) T = 1.69 seconds
Hence, this is the required solution.
Answer:
9.916\times 10^{-4}T
Explanation:
Diameter of toroid is 15 cm =0.15 m
So length of the toroid is 
Number of turns of the toriod is given as 555
Current through the toroid is 0.670 A
Magnetic field 
Answer:
1. Torque → F. Study of forces
2. C.O.G → D. Point of action of weight.
3. Plumb line → A. Line of C.O.G
Answer:
2200000 = 2.2E6 min for light from Proxima to reach earth
8.3 min from light sun to reach earth
2.2E6/8.3 = 2.56E5 times for light from Proxima
Proxima is about 256,000 times farther away than the sun
Since the sun is about 93,000,000 = 9.3E7 miles from earth
Proxima is then 9.3E7 * 2.56E5 = 2.4E13 miles away
Note - the speed of light is
3.00E8 m/s * 60 s/min / 1000 m/km = 1.8E7 km/min as given
Answer: the answer should be 6,720 decameters.