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labwork [276]
2 years ago
10

A 500 N weight is hung at the middle of a rope attached to two buildings at the same level. If the breaks in the tension exceed

1800 N, what is the minimum angle the rope can make with the horizontal? Group of answer choices 4o 8o 11o 18o
Physics
1 answer:
dedylja [7]2 years ago
6 0

Answer:

The correct choice is 8o.

Explanation:

The given weight is hanging at the mid point of the rope and the buildings are at the same level, Obtain the given equation by equating the vertical components of force,

2Tsin(φ)=W

where φ is the angle made by rope with the horizontal.

Given T=1800 N and W=500 N, the value of φ is calculated as follows,

2*1800*sin(φ)=500

sin(φ)=0.1388

φ=7.90

φ≈8o

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Substance X is in a chamber (Chamber 1) containing 10L of fluid. The concentration of substance X in this chamber is 100mmol/L.
Sidana [21]

Answer:

Explanation:

concentration of substance X in chamber 1 = 100 mmol/L

total volume of chamber 1 = 10 L

total mass of substance X in chamber 1 = 100 x 10 mmol = 1000 mmol .

When the two chamber is joined , total volume of both the chamber

= 10 L + 5 L = 15 L .

In the volume of 15 litre , substance x is uniformly distributed because it is permeable .

concentration of substance X = mass of X / total volume = 1000 mmol / 15

= 66.67 mmol / L

Hence ,

"The concentration of Substance X in Chamber 2 will never exceed 66mmol/L."

7 0
3 years ago
With fuel prices for combustible engine automobiles increasing, researchers and manufacturers have given more attention to the c
Alinara [238K]

Answer:

Then the difference of weight between the two cars are:

Δw = 14210 - 5292 = 8918 N

Explanation:

An object's weigh due to the gravitational attraction force of the earth is:

w = mg

            Where: m is the object's mass

                         g is the  gravitational acceleration in the surface earth

                         g = 9.8 m/s2

The the ultralight car's weight is:

w_{uc} = (540)(9.8)

w_{uc} = 5292 N

And the Honda Accord's weight is:

w_{HA} = (1450)(9.8)

w_{HA} = 14210 N

Then the difference of weight between the two cars are:

Δw = 14210 - 5292 = 8918 N

4 0
4 years ago
All BUT one is a function of the cell wall. That is___
Nataly [62]
The cell wall does not transfer genetic materials
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3 years ago
Read 2 more answers
5. George walks to a friend's house. He walks 750 meters North, then realizes he walked too far.
dedylja [7]

Answer:

Average speed: approximately 76.9\; {\rm m\cdot s^{-1}}.

Average velocity: approximately 38.5\; {\rm m \cdot s^{-1}} (to the north.)

Explanation:

Consider an object that travelled along a certain path. Distance travelled would be equal to the length of the entire path.

In contrast, the magnitude of displacement is equal to distance between where the object started and where it stopped.

In this question, the path George took required him to travel 750\; {\rm m} + 250\; {\rm m} = 1000\; {\rm m} in total. Hence, the distance George travelled would be 1000\; {\rm m}. However, since George stopped at a point (750\; {\rm m} - 250\; {\rm m}) = 500\; {\rm m} to the north of where he started, his displacement would be only 500\; {\rm m} to the north.

Divide total distance by total time to find the average speed.

Divide total displacement by total time to find average velocity.

The total time of travel in this question is 13\; {\rm s}.. Therefore:

\begin{aligned}\text{average speed} &= \frac{\text{total distance}}{\text{total time}} \\ &= \frac{1000\; {\rm m}}{13\; {\rm s}} \\ &\approx 76.9\; {\rm m\cdot s^{-1}}\end{aligned}.

\begin{aligned}\text{average velocity} &= \frac{\text{total displacement}}{\text{total time}} \\ &= \frac{500\; {\rm m}}{13\; {\rm s}} && \genfrac{}{}{0px}{}{(\text{to the north})}{}\\ &\approx 38.5\; {\rm m\cdot s^{-1}} && (\text{to the north})\end{aligned}.

3 0
2 years ago
How can you drop two eggs the fewest amount of times, without them breaking?​
MA_775_DIABLO [31]

Answer:

Simply drop the egg from one inch above your foot and it will not break.

Explanation:

3 0
2 years ago
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