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labwork [276]
2 years ago
10

A 500 N weight is hung at the middle of a rope attached to two buildings at the same level. If the breaks in the tension exceed

1800 N, what is the minimum angle the rope can make with the horizontal? Group of answer choices 4o 8o 11o 18o
Physics
1 answer:
dedylja [7]2 years ago
6 0

Answer:

The correct choice is 8o.

Explanation:

The given weight is hanging at the mid point of the rope and the buildings are at the same level, Obtain the given equation by equating the vertical components of force,

2Tsin(φ)=W

where φ is the angle made by rope with the horizontal.

Given T=1800 N and W=500 N, the value of φ is calculated as follows,

2*1800*sin(φ)=500

sin(φ)=0.1388

φ=7.90

φ≈8o

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Suppose you fill two rubber balloons with air, suspend both of them from the same point, and let them hang down on strings of eq
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The charge on each balloon can be found from

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1 year ago
As you ride a bicycle on the sidewalk with a speed of
mixer [17]

Answer:

1.2 seconds

Explanation:

distance = ((final speed + initial speed) * time)/2

Here given:

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  • final speed: 0 m/s

Solving steps:

3.8 = ((0 + 6.4) * time))/2

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time = 3.8/3.2

time = 1.1875 seconds ≈ 1.2 seconds

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