1st Law: Objects that are in motion tend to stay in motion. This motion can change with external forces.
<span>If you were to stop pedaling on bike while in motion, you will notice that you will keep moving. This is because a moving body (you) has inertia. If there wasn't any friction between the tires and the ground, between the axles and wheel, any air resistance, or any other force that acts against you, then you could be coasting indefinitely! </span>
<span>2nd Law: Force is equal to the mass times acceleration. </span>
<span>When you pedal, you are applying a force onto the pedal. This force is then translated through tension to apply torque onto the wheel. Turning the wheel will make you accelerate in the lateral direction. </span>
<span>3rd Law: For every action, there is an equal and opposite reaction. </span>
<span>Without this, you could pedal and pedal, but you will be not go anywhere! It is essentially the friction between the tires and the ground that propels you forward. If the ground did not apply to the tire the same amount of force that the tire was applying to the ground, the tire would not "catch" and no friction would be applied. And if there was no third law, the weight of you and your bike would "sink" into the ground because the ground would not be applying a normal force back onto you.
hope this helps and if you have any questions just hmu and ask :)</span>
the answer is c I hope this helps
Answer:
(a) 
(b) 
(c) 
Explanation:
Given that,
(a) An electron accelerated from rest through a potential difference of 100 V. The De Broglie wavelength in terms of potential difference is given by :
Where
m and e are the mass of and charge on an electron
On solving,
V = 100 V
(b) V = 1 kV = 1000 V
(c) If 
Hence, this is the required solution.
<u>The Weight </u>is a vector whose magnitude is the product of the mass m of the object and the magnitude of the local gravitational acceleration. Its always directed toward the center of the Earth.
When Venus put in a different battery with higher voltage ... no matter
what other components were in the circuit ... the voltage across the
light bulb, and the current through it, both had to increase, and the
light bulb had to shine brighter than before.
