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Lelu [443]
3 years ago
13

Particles at the very outer edge of Saturn’s A Ring are in a 7:6 orbital resonance with the moon Janus. If the orbital period of

Janus is 16 hours 41 minutes, what is the orbital period of the outer edge of Ring A?
Physics
1 answer:
vivado [14]3 years ago
3 0

Answer:

14 hours 18 minutes.

Explanation:

ratio of number of orbits, so it completes 7 orbits in the time Janus does 6.

(16*60+41)*6/7=858 minutes or 14 hours 18 minutes

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A point charge q1 = 3.0 µC is at the origin and a point charge q2 = 6.0 µC is on the x axis at x = 10 m.
UkoKoshka [18]

Answer:

a) 1.6 mN  b) -1.6 mN  c) -1.6 mN  d) 1.6 mN

Explanation:

The electrostatic force between 2 point charges, obeys the Coulomb's Law, that can be expressed as follows:

F₁₂ = k*q₁*q₂/(r₁₂)² (in magnitude)

The direction of the force, is along the  line that joins the  charges (along the x axis) and as q₁ and q₂ are of the same sign, aims away from both charges.

a) So, for the force on q₂, we have:

F₁₂ = 9*18*10⁻⁵ N = 1.6 mN (positive as it is aiming in the positive x direction)

b) The force on q1, according to Newton's 3rd Law, is just equal and opposite to the one on q2:

F₂₁ = (-9*18*10⁻⁵) N = -1.6 mN (towards the negative x direction, away from q1)

c) If q₂ were -6.0 μC, the force will be the same in magnitude, but as now both charges have different signs, they wil attract each other, so the direction of the forces will be exactly the opposite to the first case:

F₁₂ = -1.6 mN (going towards the origin, where q₁ is located)

F₂₁ =  1.6 mN (going in the positive x direction, towards q₂)

6 0
3 years ago
Read 2 more answers
An inventor develops a stationary cycling device by which an individual, while pedaling, can convert all of the energy expended
mr Goodwill [35]

Answer:

Q=94185\ J

Explanation:

Given:

  • mass of water, m=0.3\ kg
  • initial temperature of water, T_i=20^{\circ}C
  • final temperature of water, T_f=95^{\circ}C
  • specific heat of water, c=4186\ J.kg^{-1}.K^{-1}

<u>Now the amount of heat energy required:</u>

Q=m.c.\Delta T

Q=0.3\times 4186\times (95-20)

Q=94185\ J

Since all of the mechanical energy is being converted into heat, therefore the same amount of mechanical energy is required.

4 0
3 years ago
A bird flew16 km west in 5 hours, then flew 20 km east in 6 hours. what was the birdâs velocity?
Mademuasel [1]
Solve for Speed: 16+20=36 km in 11 hrs
Answer: speed = 3.27273 kilometers per hour

To solve for speed or rate use the formula for speed, s = d/t which means speed equals distance divided by time.

<span>speed = distance/time</span>

4 0
3 years ago
Ice that formed thousands of years ago is often found to contain tiny bubbles of gas. this gas came from __________. ice that fo
motikmotik
Atmosphere

Atmospheric gas from prehistoric eras is found trapped in glaciers in the form of bubbles. These gas bubbles are the basis of studying ice cores as they provide us with accurate estimates of the conditions of past climates. The bubbles allow us to determine the composition of atmospheric air, such as the carbon dioxide and methane concentrations, as well as allow us to determine air temperatures in the past.
8 0
2 years ago
Suppose a particle moves along a straight line with velocity v(t)=t2e−2tv(t)=t2e−2t meters per second after t seconds. How many
dimulka [17.4K]

Explanation:

It is given that,

Velocity of the particle moving in straight line is :

v(t)=t^2e^{-2t}\ m/s

We need to find the distance (x)  traveled by the particle during the first t seconds. It is given by :

x=\int\limits {v.dt}

x=\int\limits {t^2e^{-2t}dt}

Using by parts integration, we get the value of x as :

x=\dfrac{-(2t^2+2t+1)e^{-2t}}{4}\ meters

Hence, this is the required solution.

6 0
3 years ago
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