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3 years ago

12

If you take a number, times by 3 then add 5. You get the same as if you took the number, times by 7 then subtract 8. What is the

number?

1 answer:

lana [24]3 years ago

8 0

3x+5=7x-8
4x=13
x=13/4
the answer is 13/4

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Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago

The first figure is dilated to form the second figure.

sweet [91]

I think it is 0.9 I think

7 0

3 years ago

Find the difference <br><br><br>-2(c + 2.5) - 5(1.2c + 4)

Vikentia [17]

Answer:
|−∣=7
Explanation:

∣−∣
= |(-2-5)|
= |-2-5|
= | -7|=7

8 0

2 years ago

Find the value of X. Round the length to the nearest tenth.

Nataliya [291]

Answer:

5.5 yd

Step-by-step explanation:

The angle opposite to x is 20°

Reason: Alternate interior angles are equal

$\frac{x}{15}$ = tan 20°

x = 15 × tan 20° = 5.459553514 yd

That is 5.5 yd (answer rounded off to nearest tenth).

3 0

3 years ago

Read 2 more answers

Meenu bought two fans for ₹1200 each. She sold one at a loss of 5% and the other at a profit of 10%. Find the selling price of e

Vinvika [58]

<h3><u>Solution: </u></h3>

Overall<u> </u>CP of each fan = ₹1200 .

One is sold at a loss of 5% .

( This means if CP is ₹100, SP is ₹95 ) .

• Therefore,When CP is ₹1200 , Then SP is ₹ 1140.

$= > \frac{95}{100} \times 1200 = 1140$

Also,Second fan is sold at a profit of 10% .

It means , If CP is ₹100 , SP is ₹110.

Therefore , When CP is ₹1200 , Then SP is ₹1320.

<u>• We need to find the combined CP and SP to say whether there was an overall profit or Loss.</u><u>.</u>

Total CP = ₹ 1200 + ₹ 1200 = ₹ 2400.
Total SP = ₹ 1140 + ₹ 1320 = ₹ 2460.

Since total SP > total CP , A profit of ₹ ( 2460 - 2400 ) or ₹60 has been made ..

<h3>Hope this helps you :)</h3>

4 0

2 years ago