From the standard normal tables, obtain
P(z<1.95) = 0.9744
P(z<0.37) = 0.6443
P(z<1.32) = 0.9066
P(z<1.82) = 0.9656
P(z<1.05) = 0.8531
P(z<2.05) = 0.9798
P(z<0.03) = 0.5120
P(z<0.53) = 0.7019
Answers:
Range of z Area
-------------- ---------------------------------------
a. 0 - 1.95 0.9744
b. 0 - 0.37 0.6443
c. 1.32 - 1.82 0.9656 - 0.9066 = 0.0590
d. 1.05 - 2.05 0.9798 - 0.8531 = 0.1267
e. 0.03 - 0.53 0.7019 - 0.5120 = 0.1899
Answer:
18
Step-by-step explanation:
There are 3 meals and if she feeds her lion 6/9 each meal, you would multiply by 3. 6/9 multiplied by 3 would be 18/9. If you divide 18/9 by 1/9, you get 18.
Answer:
A)
Step-by-step explanation:
the solution of a squared equation is
x = (-b ± sqrt(b² - 4ac)) / (2a)
in our case
a = 1
b = 8
c = 22
x = (-8 ± sqrt(64 - 88))/2 = (-8 ± sqrt(-24))/2 =
= (-8 ± sqrt(4×-6))/2 = (-8 ± 2×sqrt(-6))/2 =
= -4 ± sqrt(-6) = -4 ± i×sqrt(6)
<span>Mean = 270
Standard deviation = 10
x = 255
Formula for z-score, z = (x - mean)/SD
z = (255 - 270) / 10
=> z = -15 / 10 => z = -1.5
So by referring to z-table, -1.5 correlates to 0.0668 that implies to 0.07
So 7% of the boxes of Apples weight less than 255oz.
The percentage of boxes is in the range of 255 oz and 270 oz,
Now calculating the requiring percentage 50% - 7% = 43%</span>
Answer: 
Step-by-step explanation:
Given
Sample space is 
There are 8 element in sample space which indicates the outcome of tossing a coin three times
Probability of obtaining at least one head
