Question

Easy Bucks... For what values of y does the binomial 3y−5 belong to the interval (−1; 1)?

Answer 1

Answer:

$y\in(\frac{4}{3},2$)

Step-by-step explanation:

We are given that a binomial

$3y-5$

We have to find the value of y for which binomial belongs to the interval (-1,1).

In order to find the value of y we will substitute binomial equal to zero.

$3y-5=0$

$3y=5$

$y=\frac{5}{3}$

When we substitute $y=\frac{5}{3}$ then binomial belongs to given interval because 0 lies between -1 and 1.

If substitute$3y-5=-1$

Then, we get $3y=-1+5=4$

$y=\frac{4}{3}$

When we substitute $3y-5=1$ then we get

$3y=1+5=6$

$y=\frac{6}{3}=2$

If the value of y lies between $\frac{4}{3}$ and 2 then the binomial belongs to interval (-1,1).

Answer 2

3y-5 = -1

3y=4

y = 4/3

3y-5 = 1

3y = 6

y = 2

y must be between 4/3  and 2

y must be between 1  1/3 and 2