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andrew11 [14]
3 years ago
7

Fred has 36 strawberries and 42 blueberries. He wants to use them to garnish desserts so that each dessert has the same number o

f berries, but only one type of berry. He wants as much fruit as possible on each dessert. How many berries will be on each dessert? How many desserts with each type of fruit will he have?
Mathematics
2 answers:
Andreyy893 years ago
7 0
6 berries on each dessert, 6 desserts of strawberries, 7 desserts of blueberries
timurjin [86]3 years ago
5 0

Answer:

There are 6 fruits in each dessert,

6 strawberry desserts and 7 blueberry desserts.

Step-by-step explanation:

Given,

The number of strawberries = 36,

Blueberries = 42,

∵ Each desserts of berries has the same number of berries but only one type of berries,

So, the number of fruits( either strawberry or blueberry ) in each dessert = HCF(36, 42)

= 6,

Now, the number of strawberry desserts

=\frac{\text{Total strawberries}}{\text{strawberries in each dessert}}

=\frac{36}{6}

= 6,

Similarly, the number of blueberries desserts = \frac{42}{6} = 7.

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  6

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7 0
3 years ago
A. One player places 1 red, 5 green and 3 blue tiles in Bag A, and 6 red, 4 green, and 2 blue in Bag B. What is the probability
cupoosta [38]

Answer:

\frac{8}{27} is the probability that a player draws out two tiles of the same color assuming they are drawing one tile from each bag.

Step-by-step explanation:

In each bag there are red, green, and blue tiles, meaning that no matter which color is pulled out first there is always some probability that the second tile will be the same color. So, we can set up three possible outcomes:

Red: The player pulls out a red tile first. This has a \frac{1}{9} probability of happening. Then in order to succeed for the problem, the next tile also needs to be red which has a \frac{6}{12} probability attached to it. \frac{1}{9} × \frac{6}{12}=\frac{1}{18} probability of happening.

Green: There is a \frac{5}{9} probability of the player pulling out a green tile first. In this case we want to calculate the probability of the second tile being green, which would be \frac{4}{12}. \frac{5}{9}×\frac{4}{12}=\frac{5}{27}.

Blue: There is a \frac{3}{9} probability of the first tile being blue in which case we are hoping for the second tile to be blue as well. The probability of the second tile being blue is \frac{2}{12} on its own, and them both being blue is  \frac{3}{9}×\frac{2}{12}=\frac{1}{18}

Adding \frac{1}{18}+\frac{1}{18}+\frac{5}{27} we get the answer \frac{8}{27}.

4 0
3 years ago
A person's heartbeat is 88 beats per minute. If his/her heart beats 3.1e9 times in a lifetime, how long (in whole years) does th
Anit [1.1K]
We can solve this problem by the rule of three.

88 beats-------------------1 minute
3.1*10⁹ beats------------    x

x=(3.1*10⁹ beats * 1 minute) / 88 beats=35227272.73 minutes.

Now, we express this amount of time in years.

1 year=365 days
365 days=365 day*(24 hour/1day)*(24 hour /1day)*(60 minutes /1hour)=
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525600 minutes----------------------1year
35227272.73 minutes----------------x
 
x=(35227272.73 minutes * 1year) / 525600 minutes=67.0229 years
≈ 67 years.

Answer:this person can live 67 years.

5 0
3 years ago
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