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andrew11 [14]
3 years ago
7

Fred has 36 strawberries and 42 blueberries. He wants to use them to garnish desserts so that each dessert has the same number o

f berries, but only one type of berry. He wants as much fruit as possible on each dessert. How many berries will be on each dessert? How many desserts with each type of fruit will he have?
Mathematics
2 answers:
Andreyy893 years ago
7 0
6 berries on each dessert, 6 desserts of strawberries, 7 desserts of blueberries
timurjin [86]3 years ago
5 0

Answer:

There are 6 fruits in each dessert,

6 strawberry desserts and 7 blueberry desserts.

Step-by-step explanation:

Given,

The number of strawberries = 36,

Blueberries = 42,

∵ Each desserts of berries has the same number of berries but only one type of berries,

So, the number of fruits( either strawberry or blueberry ) in each dessert = HCF(36, 42)

= 6,

Now, the number of strawberry desserts

=\frac{\text{Total strawberries}}{\text{strawberries in each dessert}}

=\frac{36}{6}

= 6,

Similarly, the number of blueberries desserts = \frac{42}{6} = 7.

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Answer:

multiply

Step-by-step explanation:

Area is measured in square units such as square inches, square feet or square meters. To find the area of a rectangle, multiply the length by the width.

6 0
2 years ago
HELP PLSS !!! Will mark as brainiest
Natasha_Volkova [10]

Answer:

1709.92cm^3

Step-by-step explanation:

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3 years ago
Graph the image of the figure after a dilation with a scale factor of 2 centered at (−2,−2). Use the Polygon tool to graph the q
kolbaska11 [484]

Answer:

  see below

Step-by-step explanation:

Every vertex moves twice as far from the center of dilation as it is in the pre-image.

Perhaps the easiest image point to find is the one at lower left. In the pre-image it is 2 units left of the center of dilation, so the image point will be 2×2 = 4 units left of the center of dilation. It will be located at (-6, -2).

Other points on the image can be found either by reference to the center of dilation, or by reference to known image points. For example, the next point clockwise is 1 left and 4 up in the pre-image, so will be 2 left and 8 up from (-6, -2) in the image. That is, the pre-image point (-5, 2) becomes image point (-8, 6). You will note that (-5, 2) is 3 left and 4 up from the center of dilation, and that (-8, 6) is 6 left and 8 up from the center of dilation (twice as far away).

5 0
3 years ago
Please need help for question number 26
kherson [118]

(8,12)(14,3)


Use midpoint formula


(X1+x2/2, y1+y2/2)


Substitute with your points


(8+14/2, 12+3/2)


Solve each


(22/2,15/2)


Cancel common factor 2


(2×(4+7)/2(1),15/2)


Simplify

(4+7/1,15/2)


This is your midpoint

(11, 15/2)




3 0
3 years ago
Can y’all help me out?
Harlamova29_29 [7]
20/x+11=10/x+3
20(x+3)=10(x+11)
20x + 60 = 10x + 110
10x = 50
x = 5
6 0
3 years ago
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