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andrew11 [14]
3 years ago
7

Fred has 36 strawberries and 42 blueberries. He wants to use them to garnish desserts so that each dessert has the same number o

f berries, but only one type of berry. He wants as much fruit as possible on each dessert. How many berries will be on each dessert? How many desserts with each type of fruit will he have?
Mathematics
2 answers:
Andreyy893 years ago
7 0
6 berries on each dessert, 6 desserts of strawberries, 7 desserts of blueberries
timurjin [86]3 years ago
5 0

Answer:

There are 6 fruits in each dessert,

6 strawberry desserts and 7 blueberry desserts.

Step-by-step explanation:

Given,

The number of strawberries = 36,

Blueberries = 42,

∵ Each desserts of berries has the same number of berries but only one type of berries,

So, the number of fruits( either strawberry or blueberry ) in each dessert = HCF(36, 42)

= 6,

Now, the number of strawberry desserts

=\frac{\text{Total strawberries}}{\text{strawberries in each dessert}}

=\frac{36}{6}

= 6,

Similarly, the number of blueberries desserts = \frac{42}{6} = 7.

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an instructor grades on a curve by assuming that grades on a test are normally distributed. If the average grade is 80 and the s
sweet [91]

Step-by-step explanation:

According to normal distribution curves following a bell curve formula, it is followed that

34% of people will lie between Mean point and one positive standard deviation

34% of people will lie between Mean point and one negative standard deviation

14% of people will lie between Mean point and two positive standard deviation

14% of people will lie between Mean point and two negative standard deviation

2% of people will lie between Mean point and three positive standard deviation

2% of people will lie between Mean point and three negative standard deviation

Now following this principle, we are given that mean score is 80 and standard deviation is 8, hence the interval for grades would be;

Grade A ; Score greater than 96

Grade B : Score greater than 88 and less than or equal to 96

Grade C : Score greater than 80 and less than or equal to 88

Grade D : Score greater than 72 and less than or equal to 80

Grade E : Score greater than 64 and less than or equal to 72

Grade F : Score less than 64

3 0
3 years ago
At which root does the graph of f(x) = (x - 5)3(x + 2)2 touch the x-axis?<br> BB<br> -2<br> 2
Svetlanka [38]

Answer:

-2

Step-by-step explanation:

if x=- 2  then f(x)=(-2-5)3(-2+2)=0

so x=-2 is correct

3 0
3 years ago
Somebody please help! And show your work!
VARVARA [1.3K]

a= 34 degrees

b= 28 degrees

c= 62 degrees

Step-by-step explanation:

First you know that b is 1/2 of 56 degrees or 28.

The triangle with the a in it is isoceles because the two sides are both radii.

In the triangle the top angle = 112 because it is a centeral angle to the 112 arc.

Angle a and opposite to a are equal and then have to be 34 degrees to equal 180.

We know two arc lengths are 112 and 56 and the one with angle a has to be 34x2 or 68.

a whole circle equals 360.

360-56-68-112 = 124

Angle c = 1/2 of 124, or 62 degrees

6 0
3 years ago
3(x-5) = 5x - (3 - x)
alina1380 [7]

Answer:

X=-4

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
How do I solve for the missing lengths?
Advocard [28]

Answer:

Part 4) ER=3\ units

Part 5) DF=9\sqrt{10}\ units

Part 6) DE=30\ units

Step-by-step explanation:

Part 4) Find ER

we know that

In the right triangle ERF

Applying the Pythagorean Theorem

EF^2=ER^2+RF^2

substitute the given values

(3\sqrt{10})^2=ER^2+9^2

solve for ER

ER^2=(3\sqrt{10})^2-9^2

ER^2=90-81\\ER^2=9\\ER=3\ units

Part 5) Find DF

we know that

In the right triangle DRF

Applying the Pythagorean Theorem

DF^2=DR^2+RF^2

substitute the given values

DF^2=27^2+9^2

DF^2=810\\DF=\sqrt{810}\ units

simplify

DF=9\sqrt{10}\ units

Part 6) Find DE

we know that

DE=DR+RE ----> by segment addition postulate

we have

DR=27\ units\\RE=ER=3\ units

substitute

DE=27+3=30\ units

3 0
3 years ago
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