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Andre45 [30]
4 years ago
5

A 200 g, 20 cm diameter plastic disk is spun on an axle through its center by an electric motor. What torque must the motor supp

ly to take the disk from 0 rpm to 1800 rpm in 4.0s?
Physics
1 answer:
Rama09 [41]4 years ago
7 0

Answer: The torque required is 0.0471 N m.

Explanation:

Mass of the disc = 200 g = 0.2 kg (1 kg =1000 g)

Radius of the disc =\frac{Diameter}{2}= 10 cm = 0.1 m(1 m = 100 cm)

Angular acceleration = \alpha

\alpha =\frac{2\pi\times 1800}{60 \times 4 sec}=15\pi rad/s^2

Moment of inertia = \frac{1}{2}\times mass\times (radius)^2=\frac{1}{2}\times0.2 kg\times (0.1 m)^2=0.001 kg m^2

Torque=\alpha \times I=0.001 kg m^2\times 15\times 3.14 rad/s^2r=0.0471 N m

The torque required is 0.0471 N m.

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