This problem provides information about the pressure and temperature ideal gases are studied at. The answer to the questions are that all molecules have the same density, 2.43x10²⁵ mol/m³ and 2.43x10¹⁹ mol/cm³.
<h3>Idela gases</h3>
In science, we can start studying gases with the concept of ideal gas, as they do not collide one to another and are assumed to be perfect spheres with no relevant interactions.
In such a way, one can conclude that the <u>number density of all ideal gasses at SATP is the same</u>, as they are assumed to be perfect spheres with equal volumes per molecule.
Moreover, when calculating the number of molecules per cubic meter, one must use the ideal gas equation as:
![PV=nRT\\\\\frac{N}{V}= \frac{P*N_A}{RT}](https://tex.z-dn.net/?f=PV%3DnRT%5C%5C%5C%5C%5Cfrac%7BN%7D%7BV%7D%3D%20%5Cfrac%7BP%2AN_A%7D%7BRT%7D)
And plug in the numbers we are given:
![\frac{N}{V}= \frac{100kPa*\frac{1000Pa}{1kPa}*6.022x10^{23}molec/mol}{8.314\frac{Pa*m^3}{mol*K}*298K}=2.43x10^{25}molec/m^3](https://tex.z-dn.net/?f=%5Cfrac%7BN%7D%7BV%7D%3D%20%5Cfrac%7B100kPa%2A%5Cfrac%7B1000Pa%7D%7B1kPa%7D%2A6.022x10%5E%7B23%7Dmolec%2Fmol%7D%7B8.314%5Cfrac%7BPa%2Am%5E3%7D%7Bmol%2AK%7D%2A298K%7D%3D2.43x10%5E%7B25%7Dmolec%2Fm%5E3)
Lastly, we can calculate the molecules per cubic centimeter by performing the following conversion:
![2.43x10^{25}\frac{molec}{m^3}*(\frac{1m}{100cm} )^3\\ \\=2.43x10^{19}\frac{molec}{cm^3}](https://tex.z-dn.net/?f=2.43x10%5E%7B25%7D%5Cfrac%7Bmolec%7D%7Bm%5E3%7D%2A%28%5Cfrac%7B1m%7D%7B100cm%7D%20%29%5E3%5C%5C%20%5C%5C%3D2.43x10%5E%7B19%7D%5Cfrac%7Bmolec%7D%7Bcm%5E3%7D)
Learn more about ideal gases: brainly.com/question/26450101