(a) 10.00V
(b) 0.5V
<h2>Explanation:</h2>(a) The power(P) supplied by a resistor of resistance (R) when a voltage(V) is passed across is given by;
P = V² / R ------------------(i)
From the question;
P = 5.00W
R = 20.00Ω
Substitute these values into equation (i) as follows;
5.00 = V² / 20.00
V² = 5.00 x 20.00
V² = 100.00
V =
Solve for V;
V = 10.00V
Therefore, the maximum voltage that can be applied without harming the resistor is 10.00V
(b) By Ohm's law the current (I) flowing through a resistor of resistance (R) when a voltage (V) is applied is given by;
V = I x R
=> I = V / R ----------------(ii)
Substitute the values of V and R into equation (ii) as follows;
I = 10.00 / 20.00
I = 0.5A
Therefore, the current through the resistor is 0.5A
Answer:
α = 0.0135 rad/s²
Explanation:
given,
t = 133 min = 133 x 60 = 7980 s
angular speed varies from 570 rpm to 1600 rpm
now,
570 rpm =
= 59.69 rad/s
1600 rpm = =
= 167.6 rad/s
using equation of rotational motion
ωf = ωi + αt
167.6 = 59.7 + α x 7980
α x 7980 = 107.9
α = 0.0135 rad/s²
Answer:
9155 years old
Explanation:
We use the following expression for the decay of a substance:
So we first estimate the value of k knowing that the half-life of the C14 is 5730 years:
so, now we can estimate the age of the artifact by solving for"t" in the equation:
which we can round to 9155 years old.
Answer:
Thus the time taken is calculated as 387.69 years
Solution:
As per the question:
Half life of = 28.5 yrs
Now,
To calculate the time, t in which the 99.99% of the release in the reactor:
By using the formula:
where
N = No. of nuclei left after time t
= No. of nuclei initially started with
(Since, 100% - 99.99% = 0.01%)
Thus
Taking log on both the sides:
t = 387.69 yrs