It is possible to have liquid water at 200°C. a)-True b)- False

An uncovered swimming pool loses 1.0 inch of water off its 1,000 ft^2 surface each week due to evaporation. The heat of vaporiza

soldi70 [24.7K]

Answer:

The affirmation is true, the cover will be worth buying

Explanation:

The equation necessary to use is

E = m*cv,

Where

cv: the heat of vaporization.

Finding the rate at which the water evaporates (m^3/week).

The swimming pool loses water at 1 inch/week off its 1,000 ft^2

Than,

1000 ft² * 1 in/wk * 1 ft/12 in = 83.33 ft³/week

To obtains the rate of mass loss it is necessary to multiply it for the density of water

83.33 ft³/week * 62.4 lb/ft³ = 5200 lb/week

Knowing the vaporization heat it is possible to find the rate of heat which is leaving the swimming pool

5200 lb/week * 1050 BTU/lb = 5460000 btu/week

Over a 15-week period, the pool loses 81.9 million BTU.

Knowing the cost of energy to heat the pool is $10.00 per million btu

The price = $819

This way, the affirmation is true, the cover will be worth buying

3 0

3 years ago

why is my ad not working? it will say we have a ad just for you but it will take forever to show me the ad

vodka [1.7K]

Explanation:

Maybe your phone is being slow. Turn of your data and turn it back on

6 0

4 years ago

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The temperature in a pressure cooker is 130 degree C while the water is boiling. Determine the pressure inside the cooker.

emmasim [6.3K]

Answer:

The pressure inside the cooker is 1.0804 atm.

Explanation:

Boiling occurs when the vapor pressure becomes equal to atmospheric pressure.

For water, At standard conditions (Pressure = 1 atm) boiling occurs at 373.15 K.

So, Standard conditions:

T₁ = 373.15 K

P₁ = 1 atm

Given ,

The water boils at Temperature = 130 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So, the temperature, T₂ = (130 + 273.15) K = 403.15 K

To find pressure inside the cooker (P₂) :

Applying Amontons's Law as:

$\frac {P_1}{T_1}=\frac {P_2}{T_2}$

So,

$P_2=\frac {P_1}{T_1} \times {T_2}$

$P_2=\frac {1 atm}{373.15 K} \times {403.15 K}$

$P_2=1.0804 atm$

Thus, The pressure inside the cooker is 1.0804 atm.

6 0

3 years ago

Two forces, one of which double the other has resultant of 280N. if the direction of the large force is reversed and the remaini

White raven [17]

Answer:

point is 16 N.If their resultant is normal to the smaller force and has a magnitude of 8 N. Then two forces are.

4 0

4 years ago

An insulated 40 ft3 rigid tank contains air at 50 lbf/in2 and 120oF. A valve connected to the tank is now opened, and air is all

goldfiish [28.3K]

Answer:

The electrical work for the process is 256.54 Btu.

Explanation:

From the ideal gas equation:

n = PV/RT

n is the number of moles of air in the tank

P is initial pressure of air = 50 lbf/in^2 = 50 lbf/in^2 × 4.4482 N/1 lbf × (1 in/0.0254m)^2 = 344736.2 N/m^2

V is volume of the tank = 40 ft^3 = 40 ft^3 × (1 m/3.2808 ft)^3 = 1.133 m^3

T is initial temperature of air = 120 °F = (120-32)/1.8 + 273 = 321.9 K

R is gas constant = 8.314 J/mol.k

n = 344736.2×1.133/8.314×321.9 = 145.94 mol

The thermodynamic process is an isothermal process because the temperature is kept constant.

W = nRTln(P1/P2) = 145.94×8.314×321.9×ln(50/25) = 145.94×8.314×321.9×0.693 = 270669 J = 270669 J × 1 Btu/1055.06 J = 256.54 Btu

5 0

3 years ago

Read 2 more answers