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Kay [80]
3 years ago
15

PLSSSSSS!!!! HELP ME I WILL MARK YOU!!!!!!! MATH!!!!!!!!!!!!!!

Mathematics
2 answers:
scoundrel [369]3 years ago
8 0

Answer:

-24

Step-by-step explanation:

-1(3^2)+(-15)

  -9+(-15)

      -24

jenyasd209 [6]3 years ago
3 0

Answer:

-24

Step-by-step explanation:

if n=-1, p=3, and q=-15, then the equation would be -1(3)^2+(-15)

Follow PEMDAS.

-1(3)^2+(-15)

-1x3^2-15

-1x9-15

-9-15

**-24**

hope this helps! : )

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nataly862011 [7]

Answer:

she has 24 shoes

Step-by-step explanation:

12 x 2(pair)=24

8 0
3 years ago
Subtract the given function and indicate the domain of the difference
maxonik [38]

Answer:

The domain is x\in (-\infty,\infty).

Step-by-step explanation:

Given functions f(x)=x^2+3x+1 and g(x)=2x^2-4x-1

Subtract these two functions:

f(x)-g(x)\\ \\=(x^2+3x+1)-(2x^2-4x-1)\\ \\=x^2+3x+1-2x^2+4x+1\\ \\=(x^2-2x^2)+(3x+4x)+(1+1)\\ \\=-x^2+7x+2

Plot these difference on the coordinate plane (see attached diagram). This function is defined for all vlues of x, so the domain is x\in (-\infty,\infty).

6 0
3 years ago
Taylor and Anya live 63 miles apart. Sometimes on a Saturday, they ride their bikes toward each other's houses and meet somewher
blondinia [14]
Im pretty sure the answer to this is 7 miles
4 0
3 years ago
Read 2 more answers
What are the solutions of the equation 9x4 – 2x2 – 7 = 0? Use u substitution to solve. tions of the equation 9
skelet666 [1.2K]

Answer:

Step-by-step explanation:

Let u^2=x^4\\u = x^2

Subbing in:

9u^2-2u-7=0

a = 9, b = -2, c = -7

The product of a and c is the aboslute value of -63, so a*c = 63.  We need 2 factors of 63 that will add to give us -2.  The factors of 63 are {1, 63}, (3, 21}, {7, 9}.  It looks like the combination of -9 and +7 will work because -9 + 7 = -2.  Plug in accordingly:

9u^2-9u+7u-7=0

Group together in groups of 2:

(9u^2-9u)+(7u-7)=0

Now factor out what's common within each set of parenthesis:

9u(u-1)+7(u-1)=0

We know this combination "works" because the terms inside the parenthesis are identical.  We can now factor those out and what's left goes together in another set of parenthesis:

(u-1)(9u+7)=0

Remember that u=x^2

so we sub back in and continue to factor.  This was originally a fourth degree polynomial; that means we have 4 solutions.

(x^2-1)(9x^2+7)=0

The first two solutions are found withing the first set of parenthesis and the second two are found in other set of parenthesis.  Factoring (x^2-1) gives us that x = 1 and -1.  The other set is a bit more tricky.  If

9x^2+7=0 then

9x^2=-7 and

x^2=-\frac{7}{9}

You cannot take the square root of a negative number without allowing for the imaginary component, i, so we do that:

x=±\sqrt{-\frac{7}{9} }

which will simplify down to

x=±\frac{\sqrt{7} }{3}i

Those are the 4 solutions to the quartic equation.

5 0
4 years ago
I NEED this answered right NOW please!!!!​
kykrilka [37]
Don’t click the link-
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