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Rzqust [24]
3 years ago
11

Please help please help please help please help please help please help look at the thingy pls help

Mathematics
1 answer:
attashe74 [19]3 years ago
3 0

Answer:

The slopes of line segments AC and AD are same or constant i.e \frac{1}{3}

Step-by-step explanation:

We need to find slopes of AC and AD and tell if they are same or not.

The formula used to calculate slope is: Slope=\frac{y_2-y_1}{x_2-x_1}

Finding slope of AC

We have A=(3,2) and C=(0,1)

Finding slope using formula:

We have x_1=3, y_1=2, x_2=0,y_2=1

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{1-2}{0-3}\\Slope=\frac{-1}{-3}\\Slope=\frac{1}{3}

So, Slope of AC is \frac{1}{3}

Finding slope of AD

We have A=(3,2) and C=(9,4)

Finding slope using formula:

We have x_1=3, y_1=2, x_2=9,y_2=4

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{4-2}{9-3}\\Slope=\frac{2}{6}\\Slope=\frac{1}{3}

So, Slope of AD is \frac{1}{3}

So, the slopes of line segments AC and AD are same or constant i.e \frac{1}{3}

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The question is incomplete. Completed question is given below the answer.

His solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

Given  

Then the solution follows thus:

Step 1: 8(x – 4) = 2(x + 2)

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An extraneous solution is a solution to an equation that emerges from the process of solving the problem but is not a valid solution to the original problem.

When 6 is substituted into the original equation, the original equation holds.

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Learn more about extraneous solution here: brainly.com/question/3751209

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Completed question:-

A student solves the following equation for all possible values of x:His solution is as follows:

Step 1: 8(x – 4) = 2(x + 2)

Step 2: 4(x – 4) = (x + 2)

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He determines that 6 is an extraneous solution because the difference of the numerators is 6, so the 6s cancel to 0.

Which best describes the reasonableness of the student’s solution?

His solution for x is correct and his explanation of the extraneous solution is reasonable.

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His solution for x is correct, but in order for 6 to be an extraneous solution, one denominator has to result in 0 when 6 is substituted for x.

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