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3 years ago

A normal distribution has a mean 20 and standard deviation 5. What is the z score that corresponds to the value x=222

Mathematics

1 answer:

sashaice [31]3 years ago

5 0

Answer: The z score that corresponds to the value x=22 is 0.4 .

Step-by-step explanation:

Given : A normal distribution has a mean 20 and standard deviation 5.

i.e. $\mu=20$

$\sigma=5$

Let x be the random selected variable.

We know that to find the z-score corresponds to the value x is given by :-

$z=\dfrac{x-\mu}{\sigma}$

For x = 22, we have

$z=\dfrac{22-20}{5}=\dfrac{2}{5}\\\\\Rightarrow\ z=0.4$

Hence, the z score that corresponds to the value x=22 is 0.4

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gulaghasi [49]

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Read 2 more answers

How am I supposed to figure this out if csc Theta(0) has a radical number on the top?

Harman [31]

$\bf csc(\theta)=\cfrac{hypotenuse}{opposite}\implies csc(\theta)=\cfrac{\sqrt{7}}{2}\cfrac{\leftarrow hypotenuse=c}{\leftarrow opposite=b}\\\\
-----------------------------\\\\
\textit{so hmm using the pythagorean theorem, we can say that}\\\\
c^2=a^2+b^2\implies \pm \sqrt{c^2-b^2}=a\qquad 
\begin{cases}
c=hypotenuse\\
b=opposite\\
a=adjacent
\end{cases}\\\\
\textit{we'll assume is the + of the root, since you're not}\\
\textit{given further info on it, that means the I quadrant}\\\\
$

$\bf -----------------------------\\\\
cos(\theta)=\cfrac{a}{c}\qquad sec(\theta)=\cfrac{c}{a}\qquad tan(\theta)=\cfrac{b}{a}\qquad cot(\theta)\cfrac{a}{b}
$

so just find the "adjacent" side, using the pythagorean theorem, and even though the square root can give you +/-, use the positive one, assuming the angle is in the 1st quadrant

keeping in mind, that the 2nd quadrant is feasible as well, since the opposite side of +2 can also be in the 2nd quadrant

but anyhow, use the I quadrant

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3 years ago