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3 years ago

Y=8-2x when x=8 the value of y

Mathematics

2 answers:

Lera25 [3.4K]3 years ago

8 0

Answer:

-8

Step-by-step explanation:

Given that x and y are two variables. they are related by the function

y =8-2x

Since x and y are related, given one value we can find the other using this equation.

In our question, given that x =8

Substitute x value in the equation

y = 8-2x

y =8-2(8) = -8

Hence answer is -8:

Verify: We verify by putting -8 for y and check whether x =8

-8=8-2x

Or 2x = 16

x =8

Verified

pantera1 [17]3 years ago

6 0

I believe your answer to this question is

8

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Please help!! What Find the Error and explain why it is wrong!

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Answer:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

Step-by-step explanation:

First image attached

The error was done in Step E, because student did not multiply $2\cdot x -8$ by the negative sign in numerator. The real numerator in Step E should be:

$3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x$

Hence, Step E must be $\frac{2\cdot x -5}{(x+4)\cdot (x-4)}$ .

Second image attached

The error was done in Step C, because the student omitted the $2\cdot a \cdot b$ of the algebraic identity $(a+b)^{2} = a^{2}+2\cdot a\cdot b +b^{2}$ . Step C must be $5\cdot x = x^{2}+4\cdot x + 4$

And further steps are described below:

Step D

$x^{2}-x+4 = 0$