Answer:
we might be starting it again soon
Step-by-step explanation:
Im in 7th and I might need help!!
Because arcsin or sin-1 only gives outputs that are in the first and fourth quadrant.
5pi / 6 is in the second quadrant.
x^2 = the first integer
(x - 1)^2 = the second integer.
x^2 - (x - 1)^2 = ?
First, let's plug a number into our equation for x.
(2)^2 - (2 - 1)^2 = ?
4 - (1)^2 = ?
4 - 1 = 3
As we can see the difference is odd but it's also the sum of the two consecutive integers.
2 + 1 = 3.
This works for all numbers. Let's plug another number into our equation for x.
(4)^2 - (4 - 1)^2 = ?
16 - (3)^2 = ?
16 - 9 = 7
4 + 3 = 7
Try any number and it will always be odd.
Answer:
Quadrant III ( C )
Quadrant IV ( D )
Step-by-step explanation:
Ordered pair ( a, b )
gives a point P on the coordinate plane
( a, b ) = ( x, y )
given : b = negative ( y-axis )
a ≠ 0 ( i.e. a = negative or positive ) ( x -axis )
Therefore point P is located in the : Third and fourth quadrants
