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masya89 [10]
3 years ago
6

Tristan has some dimes and some quarters. He has at least 20 coins worth at most $4.25 combined. If Tristan has 10 dimes, determ

ine the maximum number of quarters that he could have. If there are no possible solutions, submit an empty answer.
Mathematics
1 answer:
Dovator [93]3 years ago
7 0

Answer:

The maximum number of quarters that he could have is 13

Step-by-step explanation:

Let x represent the number of quarters he could have. If he has 10 dimes and has at least 20 coins, then

→ x + 10 >= 20

→ x >= 10    (1)

His coins worth at most $4.25. Also, it is known that 1 dollar is equal to 100 cents, 1 dime is equal to 10 cents and 1 quarter is equal to 25 cents.

→ (x * 25) + (10 * 10)  <= (4.25 * 100)

→ 25x  + 100 <= 425

→ 25x <= 325

→ x <= 13  (2)

If we combine the equation 1 and 2:

10 <= x <= 13

The maximum value of x is 13

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a. Un equipo de tenis de mesa ganó 21 juegos y perdió 12 juegos, ¿cuál es la razón entre ganados y perdidos?
True [87]

Answer:

The ratio between won and lost is \frac{7}{4}

Step-by-step explanation:

<u><em>The question in English is</em></u>

A table tennis team won 21 games and lost 12 games, what is the ratio between won and lost?

Let

x ------> the number of games won

y -----> the number of games lost

we have

x=21\ games

y=12\ games

we know that

To find the ratio divide the number of games won by the number of games lost

so

\frac{x}{y}

substitute the values

\frac{21}{12}

Simplify

\frac{7}{4}

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4 years ago
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8 0
3 years ago
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The sum of 4 consecutive integers is 78. What are the 4 integers?<br><br> Help please
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Step-by-step explanation:  if this is for a test your welcome bud.

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3 years ago
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4 years ago
How many numbers between 100 and 999 are divisible by 4?
QveST [7]
Try this solution:
1. Note, that 100 is divisible by 4, and 999 is not divisible by it, only 996. This is an arithmetic sequence.
2. a1;a2;a3;a4;...a(n) the sequence, where a1=100; a2=104; a3=108; a4=112; ... etc., and a(n)=996. n=?
3. using a formula for n-term of the sequence: a(n)=a1+d(n-1), where a(n)=996; a1=100 and d=4 (according to the condition ' is divisible by 4'). Then 100+4(n-1)=996; ⇒ 4n=900; ⇒ n=225 (including 100).

answer: 225
7 0
3 years ago
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