Let the unknown number be x. Then (1/10)x = 0.002. To solve for x, multiply both sides by 1000 to remove the decimal fraction 0.002.
Then 1000(1/10)x = 1000(0.002), or 100x = 2. Dividing both sides by x returns
x=100/2, or x= 50 (answer)
Answer: 0.75
Step-by-step explanation:
Given : Interval for uniform distribution : [0 minute, 5 minutes]
The probability density function will be :-

The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-
![P(x>1.25)=\int^{5}_{1.25}f(x)\ dx\\\\=(0.2)[x]^{5}_{1.25}\\\\=(0.2)(5-1.25)=0.75](https://tex.z-dn.net/?f=P%28x%3E1.25%29%3D%5Cint%5E%7B5%7D_%7B1.25%7Df%28x%29%5C%20dx%5C%5C%5C%5C%3D%280.2%29%5Bx%5D%5E%7B5%7D_%7B1.25%7D%5C%5C%5C%5C%3D%280.2%29%285-1.25%29%3D0.75)
Hence, the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes = 0.75
Answer:
consecutive = x+x+2
x+x+2 = 4x-20
2x+2=4x-20
2=2x-20
22=2x
x=11
Numbers are 11,13.
Hope this helps plz hit the crown :D
Answer is going to be x>-19
Answer:
2.86
Step-by-step explanation:
Add all of them together to get 20, divide by the total employees so 7, you get 2.857. Round to nearest hundredth to get 2.86