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hodyreva [135]
2 years ago
10

For a function f left parenthesis x right parenthesis equal b to the power of x comma space i f space b greater than 1 the graph

will always
Mathematics
1 answer:
tekilochka [14]2 years ago
7 0
Hello,

f(x)=b^x if b>0 then f(x)>=0 and the graph will always be creasing.
x_{1} \ \textless \  x_{2}  ==\ \textgreater \  f(x_{1}) \ \textless \  f(x_{2})
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ving as a relation, state the domain and range, then determine if it is a6.2X-2 0.-2Relation:DomainRangeFunction3 i
Travka [436]

The relation is the set of ordered pairs of point drawn in the graph

The points are:

(-2, 3), (0, 1), (2, -1), (3, -2)

So the relation is:

R = {(-2, 3), (0, 1), (2, -1), (3, -2)}

The domain is the values of x in the ordered pairs

x = -2, 0, 2, 3

The domain = {-2, 0, 2, 3}

The range is the values of y in the ordered pairs

y = 3, 1, -1, -2

Arrange them in the set

The range = {-2, -1, 1, 3}

7 0
1 year ago
If the class was going to get a class pet and 5 picked fish and 7 pick bird and 8 picked Rabbits have many students were in the
Sedbober [7]
Sum up the total number of votes.
So, 5+7+8=20 students
3 0
2 years ago
I need help. What is -8+y=-3y-2
Bond [772]
-8+y=-3y-2
-8+2=3y-y
-6=2y
y=-3
8 0
3 years ago
Read 2 more answers
1 BILLION POINTS PLEASE HELP
AlekseyPX

Answer:

False?

Step-by-step explanation:

The arrow keeps going may thats why its false

3 0
2 years ago
Write down and simplify all the terms in the expansion of (1+3x)6.Using your results to estimate the value of (0.97)6correct to
Keith_Richards [23]

Answer:

(a)\ (1 + 3x)^6 = 728x^6 + 1458x^5 + 1215x^4 + 540x^3 + 135x^2 + 18x + 1

(b)\ (1 + 3(-0.01))^6 = 0.8330

Step-by-step explanation:

Given

(1 + 3x)^6

Solving (a): Expand

To do this, we make use of pascal triangle

When the exponent is 6, the factors are: 1, 6, 15, 20, 15, 6 and 1

As a rule, the exponent of 1 will start from 0 and then increase by 1 in each term while the exponent of 3x will start from 6 and then decrease by 1 in each term.

So, we have:

(1 + 3x)^6 = 1 * 1^0 * (3x)^6 + 6 * 1^1 * (3x)^5 + 15 * 1^2 * (3x)^4 + 20 * 1^3 * (3x)^3 + 15 * 1^4 * (3x)^2 + 6 * 1^5 * (3x)^1 + 1 * 1^6 * (3x)^0

Expand

(1 + 3x)^6 = 1 * (3x)^6 + 6 *  (3x)^5 + 15  * (3x)^4 + 20 *  (3x)^3 + 15 *  (3x)^2 + 6  * (3x)^1 + 1 * (3x)^0

(1 + 3x)^6 = 1 * 728x^6 + 6 *  243x^5 + 15  * 81x^4 + 20 *  27x^3 + 15 *  9x^2 + 6  * 3x + 1

(1 + 3x)^6 = 728x^6 + 1458x^5 + 1215x^4 + 540x^3 + 135x^2 + 18x + 1

Solving (b): (0.97)^6

Rewrite as:

(0.97)^6 = (1 - 0.03)^6

Express -0.03 as 3 * -0.01

(0.97)^6 = (1 + 3(-0.01))^6

So, by comparing:

(1 + 3x)^6 and (1 + 3(-0.01))^6

x = -0.01

Recall that:

(1 + 3x)^6 = 728x^6 + 1458x^5 + 1215x^4 + 540x^3 + 135x^2 + 18x + 1

This gives:

(1 + 3(-0.01))^6 = 728(-0.01)^6 + 1458(-0.01)^5 + 1215(-0.01)^4 + 540(-0.01)^3 + 135(-0.01)^2 + 18(-0.01) + 1

Using a calculator

(1 + 3(-0.01))^6 = 0.000000000728 -0.0000001458+ 0.00001215  -0.00054  + 0.0135 -0.18 + 1

(1 + 3(-0.01))^6 = 0.83297200492

(1 + 3(-0.01))^6 = 0.8330 --- approximated

4 0
2 years ago
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