A ball is kicked upward with an initial velocity of 56 feet per second. The ball's height h (in feet) can be expressed as a func tion of time t (in seconds) by the equation h = -16t2 + 56t. How much time does the ball take to return to the ground?
1 answer:
Answer:
D) 3.50 seconds
Step-by-step explanation:
You are interested in the positive value of t such that h=0. Substituting 0 for h, we get ...
0 = -16t^2 +56t
0 = -16t(t -3.5) . . . . . factored form
The product is zero when the factors are zero. Here, the factor of interest is ...
0 = t-3.5
3.5 = t . . . . . add 3.5 to both sides
The ball takes 3.5 seconds to return to the ground .
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