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adell [148]
4 years ago
6

Negative 5X +3 equals 18

Mathematics
1 answer:
andrey2020 [161]4 years ago
6 0
-5x +3 =18
Subtract 3 from each side
-5x= 15
Divide by -5 
x= -3 
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Answer: B

Step-by-step explanation:

For the left side of the graph, the dot is not shaded so it is not equal, thus a and d are wrong.

c is wrong as well as the left side of the graph is x less than 1 and not more than so from the process of elimination, we get that the answer is B

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2 years ago
Last Wednesday, students could choose ham or turkey sandwiches for lunch. The cafeteria made 50 sandwiches in all, 5 of which we
PSYCHO15rus [73]

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90%

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50%×2 100%

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45%×2 90%

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What is tje answer 3m - m
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3 years ago
(PLEASE HELP!!!)Where does the following graph have clusters of data? Select all that apply.
grigory [225]

Answer:

1-5

Step-by-step explanation:

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8 0
3 years ago
One of the tallest buildings in a country is topped by a high antenna. The angle of elevation from the position of a surveyor on
irina1246 [14]

Answer:

a. distance of the surveyor to the base of the building = 2051.90 ft

b. height of the building = 1384 ft

c. Angle of elevation from the surveyor to the top of the antenna = 38.31°

d. Height of antenna  =  237.08 ft

Step-by-step explanation:

​The picture above is a illustration of the described event.

a = the height of the flag

b = the height of the building

c = distance of the surveyor from the base of the building

the angle of elevation from the position of the surveyor on the ground to the top of the building = 34°  

distance from her position to the top of the building  = 2475 ft

distance from her position to the top of the flag  = 2615 ft

​(a) How far away from the base of the building is the surveyor​ located?​

using the SOHCAHTOA principle

cos 34° = c/2475

c =  0.8290375726  × 2475

c = 2051.8679921

c = 2051.90 ft

(b) How tall is the​ building

The height of the building = b

sin 34° = opposite /hypotenuse

0.5591929035 = b/2475

b =  0.5591929035  × 2475

b =  1384.0024361

b =  1384.00 ft

​(c) What is the angle of elevation from the surveyor to the top of the​ antenna?

let the angle = ∅

cos ∅ = adjacent/hypotenuse

cos ∅ = 2051.90/2615

cos ∅ =  0.784665392

∅ = cos-1  0.784665392

∅ =   38.310258303

∅ =  38.31°

​(d) How tall is the​ antenna?

height of the antenna = a

sin 38.31° = opposite/hypotenuse

sin 38.31° = (a + b)/2615

sin 38.31° × 2615 = (a + b)

(a + b) =  0.6199159917  × 2615

(a + b) =  1621.0803182

(a + b) = 1621. 08 ft

Height of antenna = 1621. 08 - 1384.00  =  237.08031822 ft

Height of antenna  =  237.08 ft

8 0
3 years ago
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