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3 years ago

What is the direction of a vector that has the following components: x = -44 m y = -59 m

Physics

1 answer:

seraphim [82]3 years ago

8 0

Answer:

i dont really nnow the answer so byee

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Two<br>vectors Å and °B are such that A = 2<br>and A-B-C find the angle between them

sweet-ann [11.9K]

Answer:

hjg567 A 567

Explanation:

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3 years ago

A skier of mass 58.0 kg starts from rest at the top of a ski slope of height 70.0 m . Part APart complete If frictional forces d

AlexFokin [52]

Answer:

A) v = 31.8 m/s

B) v_f = 18.1 m/s

C) F_avg = 4130.7 N

Explanation:

A) From law of conservation of energy, we know that;

mgh = W_f + ½mv²

v is the speed at which she is going at the bottom of the slope.

Thus, making v the subject, we have;

v = √[2gh - (2W_f)/m)]

We are given;

h = 70 m

m = 58 kg

W_f = 1.04 × 10⁴ J = 10400 J

Thus;

v = √[(2 × 9.8 × 70) - (2 × 10400)/58)]

v = 31.8 m/s

B) Total force will be given by the formula;

F_t = F_k + F_r

Where;

F_k is force of kinetic friction = mg•μ_k

μ_k = 0.25

So, F_k = 58 × 9.8 × 0.25

F_k = 142.1 N

We are given force of air resistance(F_r) as 150 N

Thus;

F_t = 142.1 + 150

F_t = 292.1 N

Final velocity is gotten from the formula;

v_i² - v_f² = 2F_t•L/m

Thus;

v_f = √[v_i² - (2F_t•L/m)]

Where, v_i = 31.8 m/s, F_t = 292.1, m = 58 kg, L = 68 m

Thus;

v_f = √[31.8² - (2 × 292.1 × 68/58)]

v_f = 18.1 m/s

C) the average force exerted on her by the snowdrift as it stops her is given by the formula;

F_avg = m•v_f²/2l

F_avg = 58 × 18.1²/(2 × 2.3)

F_avg = 4130.7 N

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4 years ago

A satellite is put in a circular orbit about Earth with a radius equal to 35% of the radius of the Moon's orbit. What is its per

Debora [2.8K]

Answer:

0.21 lunar month

Explanation:

the radius of moon = r₁

time period of the moon = T₁ = 1 lunar month

The radius of the satellite = 0.35 r₁

Time period of satellite

The relation between time period and radius

$T\ \alpha\ \sqrt{r^3}$

now,

$\dfrac{T_2}{T_1}=\dfrac{\sqrt{r_2^3}}{\sqrt{r_1^3}}$

$\dfrac{T_2}{T_1}=\dfrac{\sqrt{0.35^3r_1^3}}{\sqrt{r_1^3}}$

$\dfrac{T_2}{1}=\sqrt{0.35^3}$

T₂ = 0.21 lunar month

hence, the time period of revolution of satellite is equal to 0.21 lunar month

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3 years ago

Moving waves can be described either as a function of time or as a function of

ser-zykov [4K]

<span>a. amplitude. is the answer</span>

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4 years ago

The net force on a 3.2kg toy airplane is 7N. What is the accelerator of the airplane?

mrs_skeptik [129]

Answer:

equal. is this. 0.4 That the answer

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4 years ago