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iren [92.7K]
3 years ago
14

Gamma rays

Physics
1 answer:
spayn [35]3 years ago
7 0
? is there more to this ?
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What is the density of a 15 g box measuring<br> 10 cm hy 5 cm by 2 cm?
Dvinal [7]

Answer:

The density of the box is 0.15 g/cm³

Explanation:

Given;

mass of the box, m = 15 g

dimension of the box, = 10 cm by 5 cm by 2 cm

Volume of the box, v = 10 cm x 5 cm x 2 cm = 100 cm³

The density of the box is given by;

Density = mass / volume

Density = 15 g / 100 cm³

Density = 0.15 g/cm³

Therefore, the density of the box is 0.15 g/cm³

8 0
4 years ago
All of the following are regulated by the medulla except
Fantom [35]

Answer:

D. flight or flight response.

Explanation:

im 99.999999% sure im right.

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vegan mac n cheese

always has been

6 0
4 years ago
According to the Droppler effect, what appears to happen when a light source moves further away from an observer? (20pts)
sweet-ann [11.9K]
I think so not take my answer because I think the answer is b
4 0
3 years ago
Read 2 more answers
A photographer uses his camera, whose lens has a 50 mm focal length, to focus on an object 2.5 m away. He then wants to take a p
Temka [501]

Answer:

0.004 m away from the film

Explanation:

u = Object distance

v = Image distance

f = Focal length = 50 mm

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{0.05}-\frac{1}{2.5}\\\Rightarrow \frac{1}{v}=\frac{98}{5} \\\Rightarrow v=\frac{5}{98}=0.051\ m

The image distance is 0.051 m

When u = 50 cm

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}-\frac{1}{u}=\frac{1}{v}\\\Rightarrow \frac{1}{v}=\frac{1}{0.05}-\frac{1}{0.5}\\\Rightarrow \frac{1}{v}=18\\\Rightarrow v=\frac{1}{18}=0.055\ m

The image distance is 0.055 m

The lens has moved 0.055-0.051 = 0.004 m away from the film

3 0
3 years ago
In one experiment, the students allow the block to oscillate after stretching the spring a distance A. If the potential energy s
atroni [7]

Answer:

    K = m g (A - A2)

Explanation:

In a block spring system the total energy is the sum of the potential energy plus the kinetic energy, for maximum elongation all the energy is potential

         Em = U₀ = m g A

For when the system is at an ele

Elongation A2 less than A, energy has two parts

        Em = K + U₂

       K = Em –U₂

We substitute

     K = m g A - m gA2

    K = m g (A - A2)

3 0
4 years ago
Read 2 more answers
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