Answer:
20 m/s.
Explanation:
Data obtained from the question include the following:
Initial position (d1) = 20 m
Final position (d2) = 60 m
Initial time (t1) = 1 sec
Final time (t2) = 3 secs
Velocity (v) =?
Next, we shall determine the change in position (Δd). This can be obtained as follow:
Initial position (d1) = 20 m
Final position (d2) = 60 m
Change in position (Δd) =?
Change in position (Δd) = d2 – d1
Change in position (Δd) = 60 – 20
Change in position (Δd) = 40 m
Next, we shall determine the change in time (Δt). This can be obtained as follow:
Initial time (t1) = 1 sec
Final time (t2) = 3 secs
Change in time (Δt) =?
Change in time (Δt) = t2 – t1
Change in time (Δt) = 3 – 1
Change in time (Δt) = 2 secs.
Finally, we shall determine the velocity of the object as follow:
Change in position (Δd) = 40 m
Change in time (Δt) = 2 secs.
Velocity (v) =?
Velocity (v) = Change in position (Δd) /Change in time (Δt)
v = Δd/Δt
v = 40/2
v = 20 m/s
Therefore, the velocity of the object between 1 and 3 secs is 20 m/s
