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2 years ago

6

In which number does the digit 4 have a value that is \dfrac{1}{10} 10 1 start fraction, 1, divided by, 10, end fraction times

as great as the digit 444 in the number 3.8463.8463, point, 846?

1 answer:

babymother [125]2 years ago

8 0

Answer:

The digit 4 should be in the thousand position in the number sought;

Examples

9.30<u>4</u>,

9.00<u>4</u>

Step-by-step explanation:

Here, we are required to consider decimal places of numbers

The digit 4 in the number 3.8463 is in the hundredth position

That is 0.04

We are asked to look for the number with a digit 4 that has the same value as $\frac{1}{10} \times$ the digit 4 in 3.8463

That is

$\frac{1}{10} \times 0.04 = 0.004$

Therefore, the digit 4 in the number sought should be in the thousandth position, that is 0.004

Example includes 9.304 or 9.004.

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Cos (90-theta) • cosec90-theta) =tano. How?

denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

$\cos (90 - \alpha ) = \sin \alpha$ or $\sin(90 - \alpha ) = \cos\alpha$

$cosec \: (90 - \alpha ) = \sec\alpha$ or $\sec(90 - \alpha ) = cosec\:\alpha$

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

<u></u> $\sin \alpha = \frac{1}{cosec \: \alpha }$ or $cosec \: \alpha = \frac{1}{\sin \alpha }$

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<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

$\cos (90 - \alpha ) \times cosec(90 - \alpha )$

$=> sin\alpha \times \sec\alpha$

$=> \sin\alpha \times \frac{1}{\cos\alpha }$

$=> \frac{\sin\alpha }{\cos\alpha }$

$=> \tan\alpha$ = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0

2 years ago

You supervise the feeding of dogs at a kennel you use an average of 10 1/2 pounds of dog food each day.at the rate how many poun

liq [111]

Answer:

73.5 pounds of dog food in 7 days

Step-by-step explanation:

10 1/2 x 7

10x 7 =70

1/2 x 7 = 3.5

70 + 3.5 =73.5 pounds of dog food in 7 days

6 0

2 years ago

A correction of "six less than twice the value of x" is

nordsb [41]

Answer:

2x-6

I don't know what you mean by correction, but that's in expression form.

8 0

3 years ago

Sari has 3 times as many pencil erasers asSam. Together they have 28 erasers. How many erasers does Sari have?

wel

3x +x = 28

4x = 28

x = 28/4 = 7

7x3 = 21

Sari has 21 erasers

4 0

3 years ago

SOMEONE PLEASE HELP ME! I have a few of the explanations but I'm not sure if I need more please suggest some thank you

lesantik [10]

Answer:

For tingle #1

We can find angle C using the triangle sum theorem: the three interior angles of any triangle add up to 180 degrees. Since we know the measures of angles A and B, we can find C.

$C=180-(A+B)$

$C=180-(21.24+27.14)$

$C=131.62$

We cannot find any of the sides. Since there is noting to show us size, there is simply just not enough information; we need at least one side to use the rule of sines and find the other ones. Also, since there is nothing showing us size, each side can have more than one value.

For triangle #2

In this one, we can find everything and there is one one value for each.

- We can find side c

Since we have a right triangle, we can find side c using the Pythagorean theorem

$b^2=a^2+c^2$

$4^2=2^2+c^2$

$16=4+c^2$

$12=c^2$

$c=\sqrt{12}$

$c=2\sqrt{3}$

- We can find angle C using the cosine trig identity

$cos(C)=\frac{adjacent}{hypotenuse}$

$cos(C)=\frac{2}{4}$

$C=arccos(\frac{2}{4} )$

$C=60$

- Now we can find angle A using the triangle sum theorem

$A=180-(B+C)$

$A=180-(90+60)$

$A=30$

For triangle #3

Again, we can find everything and there is one one value for each.

- We can find angle A using the triangle sum theorem

$A=180-(B+C)$

$A=180-(90+34.88)$

$A=55.12$

- We can find side a using the tangent trig identity

$tan(C)=\frac{opposite-side}{adjacent-side}$

$tan(34.88)=\frac{7}{a}$

$a=\frac{7}{tan(34.88)}$

$a=10.04$

- Now we can find side b using the Pythagorean theorem

$b^2=a^2+c^2$

$b^2=10.04^2+7^2$

$b^2=149.8$

$b=\sqrt{149.8}$

5 0

3 years ago