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Aleks04 [339]
3 years ago
6

In which number does the digit 4 have a value that is \dfrac{1}{10} 10 1 ​ start fraction, 1, divided by, 10, end fraction times

as great as the digit 444 in the number 3.8463.8463, point, 846?
Mathematics
1 answer:
babymother [125]3 years ago
8 0

Answer:

The digit 4 should be in the thousand position in the number sought;

Examples  

9.30<u>4</u>,

9.00<u>4</u>

Step-by-step explanation:

Here, we are required to consider decimal places of numbers

The digit 4 in the number 3.8463 is in the hundredth position

That is 0.04

We are asked to look for the number with a digit 4 that has the same value as \frac{1}{10} \times the digit 4 in 3.8463

That is

\frac{1}{10}  \times 0.04 = 0.004

Therefore, the digit 4 in the number sought should be in the thousandth position, that is 0.004

Example includes 9.304 or 9.004.

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Factor the expression below.
Gnom [1K]

Answer:

A. (x-5)(x-5)

Step-by-step explanation:

We need to factor x^2-10x+25 into the form (x+y)(x+y) where 2y=-10 and y^2=25

2y=-10

y=-5

So this becomes (x-5)(x-5)

Hope this helped!

4 0
3 years ago
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Got stuck can someone help me
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A billboard designer has decided that a sign should have 3 ft margins at the top and bottom and 5 ft margins on the left and rig
elixir [45]

Answer:

The width of billboard is "[x]" and the height of billboard is "[y"]. If total area of billboard is 9000 ft^2 then 9000=xy

Step-by-step explanation:

• The total width of billboard is [x]. Therefore the width of printed area will be (x-10) by excluding margin of left and right side.

• The total height of billboard is [y]. Therefore the height of printed area will be [(y-6)]  by excluding the margin of top and bottom from the total height.

• To find the printed area of billboard calculations are given below:

& 9000=xy

& y=\frac{9000}{x} \\  & A=(x-10)(y-6) \\  & A=xy-6x-10y+60 \\  & A=x\left( \frac{9000}{x} \right)-6x-10\left( \frac{9000}{x} \right)+60 \\  & A=9060-6x-\frac{9000}{x} \\

On taking the first order derivative of A

\[A'=-6+\left( \frac{90000}{{{x}^{2}}} \right)\]

& \left( \frac{90000}{{{x}^{2}}} \right)-6=0 \\          & 6{{x}^{2}}=90000 \\          & x=\sqrt{15000} \\          & y=\frac{9000}{x}=\frac{90000}{\sqrt{15000}}=10\sqrt{150} \\

• Hence \[x=10\sqrt{150}\] and \[y=\frac{900}{\sqrt{150}}\]

Learn More about Differentiation Here:

brainly.com/question/13012860

7 0
3 years ago
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Answer:

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(i used l for number of terms)

number of terms=n

S_{n}=\frac{n}{2} (first ~term+last~term)\\=\frac{n}{2} (1+2n-1)\\=n^2

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The correct answer is (A) this is because if you add 25 and 8 cents you get 32 and that becomes a negative number because they are asking how much it droped which i decreasing which is negative so your answer is -0.32 (A)
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