Answer: The correct option is (D) 
Step-by-step explanation: We are given to select the correct option that is true of the values of x and y in the diagram.
We can see from the figure that
the polar co-ordinates of the point (x, Y) are given by

The relation between the Cartesian and polar co-ordinates are as follows :

Substituting the values of polar co-ordinates of the given point i the above equations, we get

and

So, we get two equations :

Since first equation is not in the given options, so the correct one is
(D) 